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冷鏈物流交易中心擴建項目1、2冷庫物料提升機基礎(chǔ)施工方案[1](編輯修改稿)

2025-04-01 07:46 本頁面
 

【文章內(nèi)容簡介】 GB 50007— 2021)下列公式驗算: 當(dāng) e≤ b/6 時, pkmax = (Fk+ Gk)/A+ Mk/W (4- 2) pkmin = (Fk+ Gk)/A- Mk/W (4- 3) 當(dāng) e> b/6 時, pkmax = 2(Fk+ Gk)/3la (4- 4) X 方向 : 偏心距 exk = M0yk/(Fk+ Gk) = (+ ) = m e = exk = m ≤ (B1+ B2)/6 = pkmaxX = (Fk+ Gk)/S+ M0yk/Wy = (+ )/+ ≤ fa = = kPa,滿足要求。 4.基礎(chǔ)抗沖切驗算 計算公式: 按《建筑地基基礎(chǔ)設(shè)計規(guī)范》( GB 50007— 2021)下列公式驗算: Fl ≤ β hp ft am h0 (4- 5) Fl = pj Al (4- 6) am = (at+ ab)/2 (4- 7) pjmax,x = F/S+ M0y/Wy = + pjmin,x = F/S- M0y/Wy = - pjmax,y = F/S+ M0x/Wx = + pjmin,y = F/S- M0x/Wx = - pj = pjmax,x+ pjmax,y- F/S = + - = kPa (1)柱對基礎(chǔ)的沖切驗算: H0 = H1+ H2- as = + - = m X 方向: Alx = 1/2( A1+ A2)(B1+ B2- B- 2H0)- 1/4 (A1+ A2- A- 2H0)2 = (1/2) (- - 2 )- (1/4) (- - 2 )2= m2 Flx = pj Alx = = kN ab = min{A+ 2H0, A1+ A2} = min{+ 2 , } = m amx = (at+ ab)/2 = (A+ ab)/2 = (+ )/2 = m Flx ≤ β hp ft amx H0 = 0 = kN,滿足要求。 Y 方向: Aly = 1/4 (2B+ 2H0+ A1+ A2- A)(A1+ A2- A- 2H0) = (1/4) (2 + 2 + - )(- - 2 ) = m2 Fly = pj Aly = = kN ab = min{B+ 2H0, B1+ B2} = min{+ 2 , } = m amy = (at+ ab)/2 = (B+ ab)/2 = (+ )/2 = m Fly ≤ β hp ft amy H0 = = kN,滿足要求。 5.基礎(chǔ)受壓驗算 計算公式:《混凝土結(jié)構(gòu)設(shè)計規(guī)范》( GB 50010—— 2021) Fl ≤ β c β l fc Aln (4- 8) 局部荷載設(shè)計值: Fl = kN 混凝土局部受壓面積: Aln = Al = B A = = m2 混凝土受壓時計算底面積: Ab = min{3B, B1+ B2} min{A+ 2B, A1+ A2} = m2 混凝土受壓時強度提高系數(shù): β l = sq( Ab/Al) = sq() = c β l fc Aln = = kN ≥ Fl = kN,滿足要求。 6.基礎(chǔ)受彎計算 計算公式: 按《建筑地基基礎(chǔ)設(shè)計規(guī)范》 (GB 50007—— 2021)下列公式驗算: MⅠ =a12[(2l+ a39。)(pmax+ p- 2G/A)+ (pmax- p) l]/12 (4- 9) MⅡ =(l- a39。)2(2b+ b39。)(pmax+ pmin- 2G/A)/48 (4- 10) (1)柱根部受彎計算: G = = = X 方向受彎截面基底反力設(shè)計值: pminx = (F + G)/S - M0y/Wy = ( + )/ - pmaxx = (F + G)/S + M0y/Wy = ( + )/ + pnx = pminx+ (pmaxx- pminx)(2B1+ B)/[2(B1+ B2)] = + (- ) (2 ) = kPa Ⅰ Ⅰ截面處彎矩設(shè)計值: MⅠ = [(B1+ B2)/2- B/2]2{[2(A1+ A2)+ A](pmaxx+ pnx- 2G/S) + (pmaxx- pnx)(A1+ A2)}/12 = (- )2((2 + )(+ - 2 ) + (- ) )/12= kN m Ⅱ Ⅱ截面處彎矩設(shè)計值: MⅡ = (A1+ A2- A)2[2(B1+ B2)+ B](pmaxx+ pminx- 2G/S)/48 = (- )2(2 + )(+ - 2)/48= kN m Ⅰ
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