信源的率失真函數(shù)ppt課件(存儲(chǔ)版)
【正文】 i ??????的求含由1)p1(2p12)p1(p2S1S21??????????)21)(p1(1)21(p1S2S1???????第 7章 信源的率失真函數(shù) )21)(p1()x?(P2)x?(P)21(p2)x?(P)x?(PSSSS2121???????SS2SS1212p)p1()x?(P212)p1(p)x?(P????????2,1i)x?(PS/12)x?(P)2( ji21j)x?,x(Sdjji ?????的求含由第 7章 信源的率失真函數(shù) SS2S12DS2S11D2)21(p2p)p1()x/x?(P)21(p2)p1(p)x/x?(P????????)21)(p1(2p)p1()x/x?(P2)21)(p1(2)p1(p)x/x?(PS2S22DSS2S21D??????????2,1j2,1i2)x?(P)x/x?(PS)3( )x?,x(SdjiijD ji ????的含第 7章 信源的率失真函數(shù) ?????21iii l o g)x(PSD)D(RS)4( 的含SSSS211l ogSD)p(H211l ogSD)p1l og ()p1(pl ogp)21)(p1(1l og)p1()21(p1l ogpSD???????????????????第 7章 信源的率失真函數(shù) S)x?,x(d)x/x?(P)x(PDDS)5(21i21jjiijDi 求的由含 ? ?? ???SSSS2SSS2SSS2S212221212)21)(p1(2)p1(p)p1(2)21(p2p)p1(pD???????????????S211D1??? D1Dlo gS2D1D S?????第 7章 信源的率失真函數(shù) )D(H)p(H)D1l og ()D1(Dl ogD)p(H)D1l og (D1Dl ogD)p(H????????????2,1j2,1i)x/x?(P)D(RS)6( ijD ??和的不含S211lo gSD)p(H)D(R????第 7章 信源的率失真函數(shù) )D21(p)Dp1(D2)21(p2p)p1()x/x?(P)D21(p)Dp)(D1()21(p2)p1(p)x/x?(PSS2S12DS2S11D????????????????)D21)(p1()Dp1)(D1()21)(p1(2p)p1()x/x?(P)D21)(p1()Dp(D2)21)(p1(2)p1(p)x/x?(PS2S22DSS2S21D????????????????????第 7章 信源的率失真函數(shù) 0)D(H)p(H)D(R ???R(D) D p= p= 0 1 0)p(R)D(RpDD)p(H)0(R)D(R0DDm a xm a xm i nm i n????????，當(dāng)，當(dāng)?shù)?7章 信源的率失真函數(shù) 允許失真 D=1/8時(shí)的率失真函數(shù)及達(dá)到率失真函數(shù)的測試信道 ? ?? ?4/34/1)X(P10X??二進(jìn)制信源???????0110]D[失真矩陣?yán)?1 )b i t(87l o g8781l o g8143l o g4341l o g41)D(H)p(H)D(R????????D=1/8時(shí) 第 7章 信源的率失真函數(shù) 12543418581)D21(p)Dp1(D)x/x?(P12743418187)D21(p)Dp)(D1()x/x?(P12D11D????????????363543438587)D21)(p1()Dp1)(D1()x/x?(P36143438181)D21)(p1()Dp(D)x/x?(P22D21D??????????????第 7章 信源的率失真函數(shù) 等概率信源的率失真函數(shù) 等概率信源 ?????????????011101110]D[???????失真矩陣第 7章 信源的率失真函數(shù)
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