2124一元二次方程根與系數(shù)的關(guān)系-免費閱讀
【正文】 xx 21 ?042 ?? acbabxx ???21acxx ?21x 1 + x 2 = b+ b2 4 a c2a +b b 2 4 a c2axx 21 ?x 1 ? x 2 = b+ b 2 4 a c2a ? b b 2 4 a c2ax 1 =b+ b 24ac2ax 2 = b b24ac2a= 2b2a= ( b + b 2 4 a c ) ( b b 2 4 a c )4 a 2=4ac4a2= b2( b24 a c)4a2=caxx 21 .ab??
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