【正文】 lization before arithmetic operation. If ExEy, shift__My___。 times in bit. multilevel hierarchical structure of a puter memory system, 錯誤 !未找到引用源。 .22Let the word length of a puter is 32 bit, the capacity of the memory is 4MB. If the memory is addressed by half word, then its addressing space is 錯誤 !未找到引用源。 . Main memory includes 錯誤 !未找到引用源。 ② general registers in CPU。 is the lowest.( 具 體 答 案 不 知 通 用 寄 存 器 脫 機(jī) 外 部 存 儲 器 道 ) word length of a puter is 32 bit, the capacity of the memory is 64MB. If the memory is addressed by word, then its range of addressing is 錯誤 ! 未 找 到 引 用 源 。 if Ex=Ey, no shift. 問題 3 The mantissa of floating point number uses 2?s plement representation, the binary code of the mantissa before normalization is . It needs _left_ normalization, and it should shift_1_bit. 問題 4 ( ) representation is used in mantissa of floating point number. A. biased code or excess2q code B. sign magnitude C. 2?s plement D. 1?s plement 問題 5 In the representation of floating point numbers, （ ） is implicit(隱含 ) B. the radix of the number system to represent the mantissa C. mantissa D. sign bit 問題 6 For a IEEE 754 standard FloatingPoint number, its mantissa uses ( ) representation. A. biased code or excess2q code B. 1?s plement C. sign magnitude D. 2?s plement 問題 7 Which of the followings is correct: A. Exponent unit can realize addition, subtraction, multiplication and division operations. B. Mantissa unit only realize multiplication and subtraction operations. C. Exponent unit only realize addition and subtraction for exponent. D. Floating point calculator can be implemented by exponent and mantissa units. 問題 8 The maximal positive number in IEEE754 standard for 32bits format is （） A. +（ 2 – 223） 2+255 B. +（ 2 – 223） 2+127 C. +（ 1 – 223） 2+127 D. 2+127 + 227 問題 9 Exponent unit in floating point calculator can realize operations of addition, subtraction and pare. 問題 10 Which is normalized FloatingPoint number, if its mantissa is represented by 2?s plement format? A. B. C. D. 問題 11 In IEEE 754 standard, a floating point number is posed of sign bit s, exponent e, and mantissa m. 問題 12 The sign bit ?1? of a biased code number represents the number for__非負(fù)數(shù) _, while ?0? represents the number for__負(fù)數(shù) ___. 問題 13 In IEEE754 standard floating point, mantissa is coded as__原碼 __, exponent is coded as_移碼 . 問題 14 In IEEE 754 standard, the value of exponent is represented in excess128 code. 問題 15 In a algorithm for normalized floatpoint number, a number is 25 , with 2?s plement representation for mantissa. Then it ( ). A. needs left shift 2 bits of mantissa for normalized B. needs left shift 1 bit of mantissa for normalized. C. needs no normalized right normalized 問題 16 The exponent, E, of a floating point number usually uses biased code representation, which is more convenient for paring size or exponent equalization. 問題 17 The mantissa of a FloatingPoint number is represented by 2?s plement, then whether the FloatingPoint number is normalized is decided by ( ). A. mantissa?s sign bit and the first bit of mantissa?s numerical part are identical B. the sign bit of exponent and mantissa are identical C. mantissa?s sign bit and the first bit of mantissa?s numerical part are different D. the sign bit of exponent and mantissa are different 問題 18 In the representation of floating point numbers, ___基數(shù) ___ is implicit and invisible to the puter hardware. 問題 19 The purpose of using normalized floating point number is ( ). A. to expand the range of data representation avoid for overflow C. convenient for floating point operation D. to ensure maximum accuracy of representation 問題 20 ( ) representation is used in exponent of FloatingPoint number. A. biased code or excess2q code B. 1?s plement C. sign magnitude D. 2?s plement 第七章 問題 1 Indirect addressing mode is designed to facilitate the access of data arrays. 問題 2 Instruction set is a key factor to represent the performance of a puter. 問題 3 RegisterRegister (RR) addressing mode is slower than RegisterStorage (RS) addressing mode. 問題 4 The function of program control instructions is （ ） . A. to perform arithmetic and logic operations B. to move data between I/O and CPU C. to move data between memory and CPU D. to change the program executing order 問題 5 According to storage position of operand, the instruction set usually supports SS addressing mode. 問題 6 An instruction word consists of Opcode and addresses part. 問題 7 Format and function of instruction set only affect the hard structure of a puter. 問題 8 In register indirect addressing mode, the operand is in ( ). A. PC B. stack C. memory D. general register 問題 9 The operand is in a register, this addressing mode is called （ ） . A. register direct