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八年級數學上冊_整式的乘除練習題華東師大版-wenkub

2022-09-09 14:00:04 本頁面
 

【正文】 +b = xa?xb = 3?5 = 15, 答案為 B. A 說明: (c2)n?(+1)2 = c2 n?c2(n+1) = c2n?c2n+2 = c2n+2n+2 = c4n+2,所以 答案為 A. C 說明: [(? 2a2)3]5 = (? 2a2)3 5 = (? 2a2)15,所以 答案為 C. D 說明: (xy)3 = x3y3, A錯; (2xy)3 = 23x3y3 = 8x3y3, B錯; (?3x2)3 = (?3)3(x2)3 = ?27x6,C錯; (a2b)n = (a2)nbn = a2nbn, D正確, 答案為 D. C 說明: (23)4 = 23 4 = 212, A中式子正確; (? 2a)3 = (?2) 3a3 = ? 8a3, B中式子正確; (3ab)2 = 32a2b2 = 9a2b2, C中式子錯誤; (2mn2)4 = 24m4(n2)4 = 16m4n8, D中式子正確,所以 答案為 C. D 說明: (m6)6 = m6 6 = m36, A計算 正確; (a4)m = a 4m, (a 2m)2 = a 4m, B計算正確;(?xn)2 = x2n, C計算正確;當 n為偶數時, (?x2)n = (x2)n = x2n;當 n為奇數時, (?x2)n = ?x2n,所以 D不正確 ,答案為 D. 二、解答題: 1.解:由 32n+1+32n = 324得 3?32n+32n = 324, 即 4?32n = 324, 32n = 81 = 34, ∴ 2n = 4, n = 2 2.解析:因為 2m = 3, 4n = 2, 8k = 5 所以 8m+2n+k = 8m?82n?8k = (23)m?(82)n?8k = 23m?(43)n?8k = ( 2m)3?(4n)3?8k = 33?23?5 = 27?8?5 = 1080. 3.答案: x32 解: [?x2(x3)2]4 = (?x2?x3 2)4 = (?x2?x6)4 = (?x2+6)4 = (?x8)4 = x8 4 = x32. 4.答案: a 2m+n = 175 解:因為 am = ?5, an = 7,所以 a 2m+n = a 2m?an = (am)2?an = (?5)2?7 = 25?7 = 175. 2 整式的乘法 習題精選 選擇題: 1.對于式子 ?(?x2)n ?xn+3(x≠ 0),以下判斷正確的是 ( ) A. x0時其值為正 B. x0時其值為正 C. n為奇數時其值為正 D. n為偶數時其值為正 答案: C 說明: (?x2)n的符號由 n的奇偶性決定.當 n為奇數時, n+1為偶數,則只要 x≠ 0, xn+1即為正,所以 ?(?x2) n ?xn+3 = (xn+1)3,為正; n為偶數時 , n+1為奇數,則 xn+1的正負性要由 x的正負性決定,因此?(?x2) n ?xn+3 = ?(xn+1)3,其正負性由 x的正負性決定;所以正確答案為 C. 2.對于任意有理數 x、 y、 z,代數式(x?y?z)2(y?x+z)(z?x+y)的值一定是( ) A.正數 B.負數 C.非正 數 D.非負數 答案: D 說明: (x?y?z)2(y?x+z)(z?x+y) = (x?y?z)4,因此,代數式 (x?y?z)2(y?x+z)(z?x+y)的值一定是非負數,即正確答 案為 D. 3.解方程 x2?3x(x+1) = x(5?2x)+8得( ) A. x = 2 B. x = ? 1 C. x = 1 D. x = ?2 答案: B 說明:原方程變形為: x2?3x2?3x = 5x?2x2+8,8x = ?8, x = ?1,答案為 B. 4.如果長方體的長為 3a?4,寬為 2a,高為 a,則它的體積是 ( ) A. ( 3a?4) ? 2a?a = 3a3? 4a2 B. a? 2a = a2 C. ( 3a?4) ? 2a?a = 6a3? 8a2 D. 2a? ( 3a?4) = 6a2? 8a 答案: C 說明:利用長方體的體積公式可知該長方體的體積應該是長寬高,即 ( 3a?4)? 2a?a = 6a3? 8a2,答案為 C. 5.當 a = ?2時,代數式 (a4+ 4a2+16) ?a2?4(a4+ 4a2+16)的值為 ( ) A. 64 B. 32 C. ?64 D. 0 答案: D 說明: (a4+ 4a2+16) ?a2?4(a4+ 4a2+16) = a6+ 4a4+ 16a2? 4a4? 16a2?64 = (?2)6?64 = 0,答案為 D. 6.以下說法中錯誤的是 ( ) A.計算 (x?3y+4z)(?6x)的結果是?6x2?18xy+24xz B.化簡 (? m2n? mn+1) ? (? m3n)得m5n2+ m4n2? m3n C.單項式 ?2ab與多項式 3a2?2ab?4b2的積是 ? 6a3b+ 4a2b2+8ab3 D.不等式 x(x2+5x?6)?x(5x+4)x3?5的解集為x 答案: A 說明: (x?3y+4z)(?6x) = ?6x2+18xy?24xz, A錯,經計算 B、 C、 D都是正確的,答案為 A. 7.下列計算不正確的是 ( ) A. (3x?4y)(5x+6y) = 15x2+2x?24y2 B. ( 2a2?1)(a?4)?(a+3)(a2?1) = a3? 11a2+7 C. (x+2)(y+3)?(x?1)(y?2) = 5x+3y+4 D. (x?y)(x2+xy+y2)?(x+y)(x2?xy+y2) = ?2y3 答案: A 說明: (3x?4y)(5x+6y) = 15x2+18xy?20xy?24y2 =
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