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有機(jī)反應(yīng)方程式基礎(chǔ)訓(xùn)練(含答案)-閱讀頁

2025-07-09 05:46本頁面
  

【正文】 r CH3CH2Br+ H2OCH3CH2OH CH2=CH2↑+H2O 2CH3CH2OH CH3CH2OCH2CH3+H2O CH2=CHCH3+ H2O; 2 + H2O2CH3OH CH3OCH3+H2O; CH3OH+ + H2O2 + 2H2O12CH3CH2OH+O2 2CH3CHO+2H2O12CH3CH2CH2CH2OH+O2 2CH3CH2CH2CHO+2H2O12+O2 2+2H2O1CH3CH2OH+3O2 2CO2+3H2O1n+ n +(2n1)H2O1(1)CH2=CH2+H2O CH3CH2OH(2)C6H12O6 2C2H5OH+2CO2三、+H+(1)+NaOH→ +H2O;溶液由渾濁變澄清(2)+CO2+H2O→ +NaHCO3;溶液由澄清變渾濁+H+→ +H2O+OH+3Br2→ ↓+3HBr +3HNO3 +3H2On+nHCHO +(n1)H2O+Br2 +HBr+3HNO3 +3H2O+2MnO→ +2MnO2↓+2OH118種,四、+H2 CH3CH2CHO+H2 CH3CH2CH2OHAgNO3+NH3?H2O=== AgOH↓+NH4NO3;AgOH+2NH3?H2O=== Ag(NH3)2OH+2H2OAg(NH3)2OH=== [Ag(NH3)2]++OHCH3CHO+ 2Ag(NH3)2OH CH3COONH4+2Ag↓+3NH3↑+H2OCH3CH2CH2CHO+2Cu(OH)2+NaOH CH3CH2CH2COONa+Cu2O↓+3H2O2CH3CHO+O2 2CH3COOHHCHO+4Ag(NH3)2OH (NH4)2CO3+4Ag↓+6NH3↑+2H2O+4H2 CH3CH2CHO+HCN 13 1+4Cu(OH)2+2NaOH +2Cu2O↓+6H2O1(1)2CH3CH2OH+O2 2CH3CHO+2H2O (2)2CH2=CH2+O2 2CH3CHO(3)CH≡CH+H2O CH3CHO五、HCOOHHCOO+H+ CH3COOH+HCO=== CH3COO+H2O+CO2↑CH3COOH+ + H2O2CH3CH2OH+ +2H2OHCOOH+2Ag(NH3)2OH (NH4)2CO3+2Ag↓+2NH3↑+2H2OC17H35COOH+OH=== C17H35COO+ H2O C17H33COOH+Br2→ C17H33Br2COOH+ + H2OCH2=CHCOOH+H2 CH3CH2COOH(1)(C6H10O5)n+nH2O nC6H12O6;C6H12O6 2C2H5OH+2CO2;再由乙醇制乙酸(2)2CH2=CH2+O2 2CH3CHO;2CH3CHO+O2 2CH3COOH1CH3COOCH2CH3+H2O CH3COOH+CH3CH2OH1HCOOCH3+NaOH HCOONa+CH3OH
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