eda課程設(shè)計報告搶答器-展示頁
2025-05-22 22:06本頁面
【正文】 鎖 計數(shù) 報警Abstract Responder is the answer for the quiz participants to answer in the design when a priority decision circuit, and the race can be divided into several groups, answer in each group on the host issues raised in the shortest possible time to make judgments , and press the answer in answer key. After pressing the button when the first person, then the display shows the number of the group, the corresponding lights, while other groups will be key circuit block, it does not work. If the answer in time, no answer in, the alarm lights. Answering questions, all the keys from the host to restore and restart the next round of the Responder. So to plete the answering device logic functions, the circuit should include Responder identification module, Responder counting module, alarm module, decoding module, frequency module. KEY: Responder Identification Blockade Count Alarm一、 設(shè)計要求，分別用4個按鈕S0～ S3表示。3．搶答器具有鎖存與顯示功能。選手搶答實行優(yōu)先鎖存，優(yōu)先搶答選手的編號一直保持到主持人將系統(tǒng)清除為止。二、方案設(shè)計與論證 概述將該任務(wù)分成五個模塊進(jìn)行設(shè)計，分別為：搶答器鑒別模塊、搶答器計時模塊、報警模塊、分頻模塊、譯碼模塊。其中有四個搶答信號s0、sss3；搶答狀態(tài)顯示信號states；搶答與警報時鐘信號clk2；系統(tǒng)復(fù)位信號rst；警報信號warm。其中有搶答時鐘信號clk1；系統(tǒng)復(fù)位信號rst；搶答使能信號start；無人搶答警報信號warn；計時中止信號stop；計時十位和個位信號tb，ta。 譯碼模塊：在這個模塊中主要實現(xiàn)搶答過程中將BCD碼轉(zhuǎn)換成7段的功能。 頂層文件：在這個模塊中是對前五個模塊的綜合編寫的頂層文件。use 。entity xuanshou is port(rst,clk2:in std_logic。 states:buffer std_logic_vector(3 downto 0)。warm:out std_logic)。architecture one of
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