17_牛頓第二定律教案(新人教必修1)5篇-文庫(kù)吧資料
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【正文】 ____,b=={x|2x2+x≤(14)x－2,x∈R}，則函數(shù)y=、解答題(共30分)11.(9分)設(shè)A=am+a－m，B=an+a－n(m＞n＞0，a＞0且a≠1)，判斷A，.(10分)已知函數(shù)f(x)=a－22x+1(a∈R)，求證：對(duì)任何a∈R,f(x).(11分)設(shè)0≤x≤2，求函數(shù)y=42a2x+a2+：（略）小結(jié)： 課后作業(yè)：（略）用心 愛(ài)心 專心 則第四篇：英語(yǔ)：unit1《Friendship》教案2(新人教必修1)（精選）Period 3 Learning about language Teaching aims: discover and learn to use some words and enable students to rewrite sentences using direct or indirect speech learn more information about cultivate the spirit of cooperation, selfteaching and procedures: Step 1 Revision something about “Anne’s best friend” by using some TrueorFalse sentences 1)A friend would laugh at you.（）2)Anne lived in Amsterdam in the Netherlands during World War II.（）3)She and her family hid away for one year before they were discovered.（）4)She kept a diary as others did.（）5)She was fond of nature.（）6)She stayed awake in the night because she couldn’t sleep well.（）7)She couldn’t go out as she liked.（） the sentences students think wonderful or difficult to sentences 1)She and her family hid away for nearly twentyfive months before they were )I wonder if it’s because I haven’t been able to be outdoors for so long that I’ve grown so crazy about everything to do with )There was a time when a deep blue sky, the song of the birds, moonlight and flowers could never have kept me )The dark, rainy evening ,the wind, the thundering clouds held me entirely in their )It was the first time in a year and a half that I’d seen the night face to 2 Language points crazy about …狂熱,癡迷be crazy about … cousin grows crazy about puter through 1).To examine carefully 仔細(xì)閱讀或研究I went through the students’ papers last ).To experience 經(jīng)歷，遭受或忍受You really don’t know what we went through while working on this continue to be in a particular state or situatioin 系動(dòng)詞，表是狀態(tài)。8232。247。1246。2－x的圖象，只需將函數(shù)y=(12)x的圖象() （2）函數(shù)y=|2x－2|的圖象是()（3）當(dāng)a≠0時(shí)，函數(shù)y=ax+b和y=bax的圖象只可能是()（4）當(dāng)0 （5）若函數(shù)y=a2x+b+1(a0且a≠1,b為實(shí)數(shù))的圖象恒過(guò)定點(diǎn)(1，2)，則b=______.（6）已知函數(shù)y=(12)|x+2|.①畫(huà)出函數(shù)的圖象；②由圖象指出函數(shù)的單調(diào)區(qū)間并利用定義證明.(7)設(shè)a、b均為大于零且不等于1的常數(shù)，下列命題不是真命題的是()用心 愛(ài)心 專心=a的圖象與y=a的圖象關(guān)于y軸對(duì)稱=a的圖象和y=b的圖象關(guān)于y軸對(duì)稱，則ab=1 －xxxa22－1,則a1 ,則ab b2關(guān)于單調(diào)性（1）若－1－xx－xx（2）下列各不等式中正確的是() A.()3()3()3252C.()3()3()3 52212121211B.()3()3()3225D.()3()3()3***1211(x+1)(3－x)（3）.函數(shù)y=(2－1)的單調(diào)遞增區(qū)間是()A.(1，+∞)C.(1，3)B.(－∞，1)D.(－1，1)(4).函數(shù)y=()2xx+x+2為增函數(shù)的區(qū)間是()(5)函數(shù)f(x)=a－3a+2(a0且a≠1)的最值為_(kāi)_____.(6)已知y=(數(shù).(7)比較52x+12x12)xx+22+1，求其單調(diào)區(qū)間并說(shuō)明在每一單調(diào)區(qū)間上是增函數(shù)還是減函與5x+22的大小關(guān)于奇偶性（1）已知函數(shù)f(x)= m（2）求函數(shù)y=1x的定義域51x1（3）函數(shù)f(x)=3－x－1的定義域、值域是……()，值域是R，值域是(0，+∞) ，值域是(－1，+∞) （4）函數(shù)y=1x的定義域是______ 5x11(5)求函數(shù)y=ax1的定義域(其中a＞0且a≠1)關(guān)于值域（1）當(dāng)x∈［－2,0］時(shí)，函數(shù)y=3x+1－2的值域是______（2）求函數(shù)y=4x+2x+1+1的值域.（3）已知函數(shù)y=4x－39247。1246。布置作業(yè)：書(shū)114/3~6；P122/5；頂尖P104/變式2；P105/1115第三篇：高中數(shù)學(xué)《指數(shù)函數(shù)》教案1 新人教A版必修1（二）教學(xué)目標(biāo)：鞏固指數(shù)函數(shù)的概念和性質(zhì) 教學(xué)重點(diǎn)：指數(shù)函數(shù)的概念和性質(zhì) 教學(xué)過(guò)程：本節(jié)課為習(xí)題課,可分以下幾個(gè)方面加以練習(xí): 備選題如下:關(guān)于定義域x（1）求函數(shù)f(x)=230。=小結(jié):若給物體一定的初速度,當(dāng)μ＝tgθ時(shí),物體沿斜面勻速下滑；當(dāng)μ＞tgθ（μmgcosθ＞mgsinθ）時(shí),物體沿斜面減速下滑；當(dāng)μ＜tgθ（μmgcosθ＜mgsinθ）時(shí),物體沿斜面加速下滑.（3）靜止在水平地面上的物體的質(zhì)量為2 kg,在水平恒力F推動(dòng)下開(kāi)始運(yùn)動(dòng),4 s末它的速度達(dá)到4 m/s,此時(shí)將F撤去,又經(jīng)6 s物體停下來(lái),如果物體與地面的動(dòng)摩擦因數(shù)不變,求F的大小.解析:物體的整個(gè)運(yùn)動(dòng)過(guò)程分為兩段,前4 s物體做勻加速運(yùn)動(dòng),后6 s內(nèi)物體的加速度為a1=v04=m/s2=1m/s2 ① t14設(shè)摩擦力為Fμ,由牛頓第二定律得FFm=ma1 ② 后6 s內(nèi)物體的加速度為a2=0v42=m/s2=m/s2 ③ t263物體所受的摩擦力大小不變,由牛頓第二定律得Fm=ma2 ④ 由②④可求得水平恒力F的大小為F=m(a1a2)=2180。180。cos30176。(sin30176。角斜向上的拉力F作用時(shí)沿水平面做勻加速運(yùn)動(dòng),求物體的加速度是多大?(ｇ取10 m/s)解析:以物體為研究對(duì)象,其受力情況如圖所示,建立平面直角坐標(biāo)系把F沿兩坐標(biāo)軸方向分解,則兩坐標(biāo)軸上的合力分別為2Fx=FcosqFmFy=FN+FsinqG,向上的加速度ａｘ 物體沿水平方向加速運(yùn)動(dòng),設(shè)加速度為ａ,則ｘ軸方＝ａ,ｙ軸方向上物體沒(méi)有運(yùn)動(dòng),故ａy＝０,由牛頓第二定律得Fx=max=ma,Fy=may=0所以FcosqFm=ma,FN+FsinqG=0 以上三式代入數(shù)據(jù)可解得 用正交分解法來(lái)解.又有滑動(dòng)摩擦力Fm=mFN= m/s小結(jié):當(dāng)物體的受力情況較復(fù)雜時(shí),根據(jù)物體所受力的具體情況和運(yùn)動(dòng)情況建立合適的直角坐標(biāo)系,利（2）一斜面AB長(zhǎng)為10 ｍ,傾角為３０176。例2：書(shū)P113/例題：鞏固前面的解題步驟和規(guī)
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