微機(jī)原理與接口技術(shù)(清華第二版)第四章作業(yè)-文庫(kù)吧資料
2025-07-05 13:19本頁(yè)面
【正文】 D BL,30H MOV MAX,BL MOV DL,BL MOV AH,02H INT 21H MOV AH,4CH INT 21HCODE ENDS END START DATA SEGMENT BLOCK DB 1,1,4,3,8,9,5,3,1,2 COUNT EQU $BLOCK MAX DB ?DATA ENDSSTACK SEGMENT STACK DB 100 DUP(0)STACK ENDS CODE SEGMENT ASSUME CS:CODE,DS:DATA,SS:STACKSTART:MOV AX,DATA MOV DS,AX MOV SI,OFFSET BLOCK MOV BL,0 MOV AH,0 MOV CX,COUNT，將內(nèi)存中N個(gè)無(wú)符號(hào)數(shù)據(jù)從大到小排序后輸出顯示LOP1:MOV SI,CX MOV DI,1 LEA BX,BUFLOP2:MOV AL,[BX] CMP AL,[BX+1] JAE LOP3 XCHG AL,[BX+1] MOV [BX],AL MOV DI,0LOP3:INC BX LOOP LOP2 CMP DI,0 JNZ OK MOV CX,SI LOOP LOP1OK: MOV CX,NUM LEA BX,BUFOK1: MOV AL,[BX] CBW CALL DISPLAY MOV DL,39。 MOV [DI],AL MOV DX,OFFSET NBUF MOV AH,09H INT 21H MOV AH ,4CH INT 21HCODE ENDS END STARTDATA SEGMENT MBUF DB 5,8,3,7,5 COUNT EQU $MBUF NBUF DB 6 DUP(?)DATA ENDSCODE SEGMENT ASSUME CS:CODE,DS:DATASTART:MOV AX,DATA MOV DS,AX MOV SI,OFFSET MBUF MOV DI,OFFSET NBUF MOV CX,COUNT ADD SI,CX20．編寫(xiě)程序，將內(nèi)存中某數(shù)據(jù)塊中的正數(shù)和負(fù)數(shù)分開(kāi)，并分別將這些正數(shù)和負(fù)數(shù)送同一數(shù)據(jù)段的兩個(gè)緩沖區(qū)中，并在屏幕上顯示正數(shù)和負(fù)數(shù)的個(gè)數(shù)（數(shù)據(jù)自定）
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