【正文】 c )。 printf ( The original cost of the item is: )。 } e=1+1/1!+1/2!+1/3!+1/4!+1/5!+1/6!+1/7!+1/8!+1/9!= 6/2/2022 Chapter 6 Decision Making and Looping The present value (popularly known as book value) of an item is given by the relationship. P = c(1d)n where c = original cost d = rate of depreciation (per year) n = number of years P = present value after n years If P is considered the scrap value at the end of useful life of the item, write a program to pute the useful life in years given the original cost, depreciation rate, and the scrap value. The program should request the user to input the data interactively. 6/2/2022 Chapter 6 Decision Making and Looping main ( ) { float c, d, p。 } while ( item = ERROR )。 printf ( +1/%d!, m )。 item = / n。 i = m。 printf ( e=1 )。 int i, m = 1。 } } 6/2/2022 Chapter 6 Decision Making and Looping Write a program to pute the value of Euler39。 j = 18。 i =12 ) printf ( %18s, **** )。 else if ( i =10 amp。amp。 i++ ) { printf ( \n )。 for ( i = 1。 printf ( %ld, n % 2 )。 j i。 i ) { n = number。 for ( i = m。 m ++。 n = number。 scanf ( %ld, amp。 int m = 0, i, j。 i++ ) printf ( _ )。 } } for ( i = 1。 j++ ) { x = i + *j。 for ( j = 0。 i = 9。 i++ ) printf ( \t0.%d, i)。 for ( i = 1。 i++ ) printf ( _ )。 for ( i = 1。 int i, j。 } printf ( The number of persons in the age group 50 to 60 is %d.\n, count )。 if ( age 50 || age 60 ) continue。 scanf ( %d, amp。 i = 100。 } } 6/2/2022 Chapter 6 Decision Making and Looping Write a program to read the age of 100 persons and count the number of persons in the age group 50 to 60. Use for and continue statements. 6/2/2022 Chapter 6 Decision Making and Looping main ( ) { int age, count = 0, i。 j++ ) printf ( * )。 for ( j = 1。 j = 5 i。 i = 1。 } } 6/2/2022 Chapter 6 Decision Making and Looping main ( ) /* (b) */ { int i, j。 j++ ) printf ( %d, i )。 i++ ) { for ( j = 1。 for ( i = 1。ch )。 } } printf ( \nPress enter key to continue... )。 pp = v。 n = 8。 printf ( \n%.2f: , r)。 r 。 else printf ( %d years, n )。 n = 8。 p = p + 1000 ) { printf ( \nPrincipal amount: %.0f\nrate , p )。 for ( p = 1000。 float p, pp, r, v。 x to power n = %f\n, x, n, y )。 printf ( \nx = %f。 count = n。n)。 scanf ( %f %d, amp。 float x, y。 i ++。 f2 = f。 f = f1 + f2。 printf ( %12ld , f )。 scanf ( %d, amp。 int i = 2, m。 /* number is decreased by 10 times */ } printf ( The sum of the digits is %d.\n, sum )。 while ( n != 0 ) { sum = sum + n % 10 。 scanf ( %ld, amp。 int sum = 0。 } printf ( %ld\n, n )。 while ( m = 1 ) { n *= m。m )。 printf ( Please input a number: )。 /* number is decreased by 10 times */ } } 6/2/2022 Chapter 6 Decision Making and Looping The factorial of an integer m is the product of consecutive integers from 1 to m. That is, factorial m = m! = m (m1) …… 1. Write a program that putes and prints a table of factorials for any given m. 6/2/2022 Chapter 6 Decision Making and Looping main ( ) { int m。 while ( n != 0 ) { printf ( %d, n % 10 )。 scanf ( %ld, amp。} } 6/2/2022 Chapter 6 Decision Making and Looping Given a number, write a program using while loop to reverse the digits of the number. For example, the number 12345 should be written as 54321. (Hint: Use modulus operator to extract the last digit and the integer division by 10 to get the n1 digit number from the n digit number.) 6/2/2022 Chapter 6 Decision Making and Looping main ( ) { long n。 if ( f 0 ) printf(There are no real roots!\n)。 else if ( a == 0 ) printf(There is only one root: %.2f.\n, c/b)。amp。 printf ( About %.2fx*x + %.2fx + %.2f = 0: , a, b, c )。 scanf ( %f, amp。b )。 printf ( b = )。 scanf ( %f, amp。 printf ( Please input the value of a, b and c in the quadratic equation:\n ax*x + bx + c = 0\n )。 printf ( y = %d\n, x 0 ? 1 : x 0 ? 1 : 0 )。 scanf ( %f, amp。 } 6/2/2022 Chapter 5 Decision Making and Branching main ( ) /* (c) */ { float x。 else if ( x == 0 ) printf ( y = 0\n )。x )。 printf ( Please input the value of x: )。 } else printf ( y = 0\n )。 if ( x != 0 ) { if ( x 0 ) printf ( y = 1\n )。 scanf ( %f, amp。 } 6/2/2022 Chapter 5 Decision Making and Branching Write a program that will read the value of x and evaluate the following using (a) nested if statements (b) else if statements, and (c) conditional operator ? : ??????????010001xf o rxf o rxf o ry6/2/2022 Chapter 5 Decision Making and Branching main ( ) /* (a) */ { float x。 default: discount = 。 case 2: discount = 。 case 1: discount = 。 } else switch ( (int) (price1)/100 ) { case 0: discount = 。 break。 break。 break。m39。price )。 printf ( Price: )。scanf ( %c, amp。 char category。 else printf ( Not admitted\n )。amp。amp。amp。chem )。 printf ( Chemistry: )。 scanf ( %f, amp。math )。 printf ( Mathematics: )。 } 6/2/2022 Chapter 5 Decision Making and Branching Admission to a professional course is subject to the following conditions: (a) Marks in Mathematics = 60 (b) Marks in Physics = 50 (c) Marks in Chemistry = 40 (d) Total in all three subjects = 200 or Total in Mathematics and Physics = 150 Given the marks in the three subjects, write a program to process the applications to list the eligible candidates. 6/2/2022 Chapter 5 Decision Making and Branching main ( ) { float math, phy, chem。 if ( a*d c*b == 0) printf ( Error: the denominator i