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specific circumstances, properly addressed. 畢業(yè)設(shè)計(jì) (外文 翻譯 ) 7 雙閉環(huán)直流調(diào)速系統(tǒng)的說(shuō)明 一、系統(tǒng)分析與綜合 ( 1)在轉(zhuǎn)速、電流雙閉環(huán)調(diào)速系統(tǒng)中,若要改變電動(dòng)機(jī)的轉(zhuǎn)速,應(yīng)調(diào)節(jié)什么參數(shù)?改變轉(zhuǎn)速調(diào)節(jié)器的放大倍數(shù) Kn 行不行?改變電力電子變換器的放大系數(shù) Ks行不行?改變轉(zhuǎn)速反饋系數(shù) ? 行不行?若要改變電動(dòng)機(jī)的堵轉(zhuǎn)電流,應(yīng)調(diào)節(jié)系統(tǒng)中的什么參數(shù)? 答:若要改變電動(dòng)機(jī)的轉(zhuǎn)速,改變轉(zhuǎn)速調(diào)節(jié)器的放大倍數(shù) Kn 和電力電子變換器的放大系數(shù) Ks 都不行,穩(wěn)定時(shí) ? n=Un=Un*,所以只有改變給定 值 Un*和反饋系數(shù)? 才行。s stall current, only need to change the same value given Uim * and feedback coefficient, because the stability, Uim * = Idm, can be drawn from the type (2) Speed, the current double closedloop speed control system when the steadystate operation, the two regulator input voltage and output voltage deviation is the number? A: The speed and current dual closedloop speed control system when the steadystate operation, the two regulators are the input bias voltage is zero, by the formula n = Un = Un *, n = n。 Double Loop DC Speed Control System Description 工 學(xué) 部 專 業(yè) 自動(dòng)化 班 級(jí) 學(xué) 號(hào) 姓 名 指導(dǎo)教師 負(fù)責(zé)教師 畢業(yè)設(shè)計(jì) (外文 翻譯 ) 1 Double Loop DC Speed Control System Description Ⅰ .system analysis and synthesis 1. Analysis ( 1) In the speed and current dual closedloop speed control system, in order to change the motor speed, what parameters should be regulating? Change speed regulator Kn magnification work? Power electronic converter to change the magnification factor Ks work? Change the speed of the feedback coefficient of work? To change the motor39。s stall current system should adjust the parameters of what? A: To change the motor speed, change speed regulator Kn magnification and power electronic converters will not work magnification factor Ks, stable when n = Un = Un *, so the only change in the value of a given coefficient of Un * and feedback before. To change the motor39。 Uim * = Idm, Idm = Idl. (3) In the speed and current dual closedloop speed control system, the two regulators are PI regulator. When the system is running with rated load, the speed feedback line suddenly disconnected, the system reenter the steadystate, the current regulator is the input bias voltage to zero? Why? A: When the system is running with rated load, the speed feedback line suddenly disconnected, then Un = 0, = Un * Un = Un *, so that Ui to reach Uim, 0, rate of increase in n, when the system after reentering the steadystate , that is, Id = Idl, then, = Uim * Idl 0, are no longer changes, changes in rotational speed n is no longer, but at this time than the rotational speed n at the time of the feedback line speed to break big. (4) Why is the speed with integral control system is not static poor? A: Speed regulator integral system, to achieve nonstatic error is due to the characteristics of integral control regulator, that is, the accumulation of points and the role of memory. 畢業(yè)設(shè)計(jì) (外文 翻譯 ) 2 (5) Doubleloop speed control system (PI), load changes, Idl Idm, asked bicyclol speed control system ASR and ACR howconditioning, t