gprs-gn接口信令流程(參考版)
2025-05-18 00:57本頁面
【正文】 GPRSGn 接口信令流程 一 ． 路由區(qū)更新 間的路由區(qū)更新 (1)當(dāng) Ms 發(fā)起 PDP 上下文激活時 N e w S G S N G G S NO l d S G S N3 . S G S N C o n t e x t R e q u e s t3 . S G S N C o n t e x t R e s p o n s e4 . S G S N C o n t e x t A c k n o w l e d g e5 . F o r w a r d P a c k e t s( D o w n l i n k U s e r D a t a )6 . U p d a t e P D P C o n t e x t R e q u e s t6 . U p d a t e P D P C o n t e x t R e s p o n s e1 . C r e a t e P D P C o n t e x t R e q u e s t1 . C r e a t e P D P C o n t e x t R e s p o n s eT E I D = 0 T E I D _ D = 1 T E I D _ C = 2I M S I = 4 6 0 N S A P I = 5 P D P A d r e s s = 1 0 . 2 3 7 . 4 9 . 2 1 5（ 靜 態(tài) I P 時 存 在 ） T E I D = 2 T E I D _ D = 3 T E I D _ C = 4P D P A d r e s s = 1 0 . 2 3 7 . 4 9 . 2 1 5（ 動 態(tài) I P 時 存 在 ） 2 . U p l i n k U s e r D a t a2 . D o w n l i n k U s e r D a t aT E I D = 3 T E I D = 1T E I D = 0 T E I D _ C = 5T E I D = 5 T E I D _ C = 6 I M S I = 4 6 0 N S A P I = 5 P D P A d r e s s = 1 0 . 2 3 7 . 4 9 . 2 1 5U p T E I D _ D = 3 U p T E I D _ C = 4T E I D = 6 T E I D _ D _ I I = 7T E I D = 7T E I D = 4 T E I D _ D = 8 T E I D _ C = 9或 者T E I D = 0 I M S I = 4 6 0 N S A P I = 5T E I D _ D = 8 T E I D _ C = 9T E I D = 9 T E I D _ D = 1 0 T E I D _ C = 1 1 7 . D o w n l i n k U s e r D a t a7 . D o w n l i n k U s e r D a t aT E I D = 1 0 T E I D = 88 . D e l e t e P D P C o n t e x t R e q u e s t8 . D e l e t e P D P C o n t e x t R e s p o n s eT E I D = 1 1T E I D = 95 . F o r w a r d P a c k e t s( U p l i n k U s e r D a t a )T E I D = 38 . D e l e t e P D P C o n t e x t R e q u e s t8 . D e l e t e P D P C o n t e x t R e s p o n s eT E I D = 9T E I D = 1 1F L O W 1F L O W 2F L O W 3 說明： 1．在 Update PDP Context Request中，當(dāng) 隧道版本由 GTP版本 0改變?yōu)榘姹?1，隧道端標(biāo)識符置全 0 (2)當(dāng)網(wǎng)絡(luò)發(fā)起 PDP 上下文激活時 N e w S G S N G G S NO l d S G S N3 . S G S N C o n t e x t R e q u e s t3 . S G S N C o n t e x t R e s p o n s e4 . S G S N C o n t e x t A c k n o w l e d g e5 . F o r w a r d P a c k e t s( D o w n l i n k U s e r D a t a )6 . U p d a t e P D P C o n t e x t R e q u e s t6 . U p d a t e P D P C o n t e x t R e s p o n s e1 . C r e a t e P D P C o n t e x t R e q u e s t1 . C r e a t e P D P C o n t e x t R e s p o n s eT E I D = 4 T E I D _ D = 1 T E I D _ C = 2I M S I
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