復(fù)雜網(wǎng)絡(luò)nr法潮流分析與計算的設(shè)計課程設(shè)計(參考版)
2025-06-27 12:08本頁面
【正文】 四、結(jié)果分析及結(jié)論 B1 = Columns 1 through 5 0 + 0 + 0 + + 0 + + 0 + + 0 0 + 0 Columns 6 through 7 0 0 0 0 0 0 0 0 B2 = 0 0 0 0 + 0 0 + 0 0 + 0 0 + 0 0 0 導(dǎo)納矩陣 Y= Columns 1 through 5 0 0 + 0 0 0 0 + + 0 + 0 + + 0 0 0 + + 0 + 0 + 0 0 0 0 0 + Column 6 0 0 0 0 0 + 0 功率方程第(1)次差值： Columns 1 through 10 0 0 Columns 11 through 12 0 形成的第(1)次Jacobi矩陣： Columns 1 through 10 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Columns 11 through 13 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Jacobi矩陣第(1)次消去運(yùn)算 Columns 1 through 10 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Columns 11 through 13 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Jacobi矩陣第(1)次回代運(yùn)算 Columns 1 through 10 0 0 Columns 11 through 12 0 各個節(jié)點(diǎn)電壓模 0 功率方程第(2)次差值： Columns 1 through 10 0 0 Columns 11 through 12 形成的第(2)次Jacobi矩陣： Columns 1 through 10 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Columns 11 through 13 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Jacobi矩陣第(2)次消去運(yùn)算 Columns 1 through 10 0 0 0 0 0 0 0
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鄂ICP備17016276號-1