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ve been great at all the unglamorous stuff that often goes unnoticed in the stands but not by your teammates. It is as though their entire tournament has been preparation for the final. In Johnathan Thurston, Cooper Cronk, Cameron Smith and either Billy Slater or Greg Inglis at fullback they have a spine that is unmatched in rugby league. They ha ve played in so many highpressure games a priceless asset going into Saturday. The Kiwis are a lot less experienced but winning a dramatic match like their semifinal against England will do wonders for their confidence. They defeated Australia in the Four Nations final in 2020 and the last World Cup, and know they can rise to the big 專業(yè)好文檔 8 occasion. 。s Josh Charnley in the opening game of the tournament. That could be classed as a weakness, a team undercooked but I have been impressed by the Kangaroos39。s actions. CSKA said they were surprised and disappointed by Toure39。s 21 win. Michel Platini, president of European football39。s Premier League match at Chelsea on Sunday. I am going to be at the match tomorrow and I have asked to meet Yaya Toure, he told BBC Sport. For me it39。s antiracism taskforce, is in London for the Football Association39。s top try scorer with nine, closely followed by TuivasaSheck with eight. But it is recently named Rugby League International Federation player of the year Sonny Bill Williams who has attracted the most interest in the tournament so far. The Kiwi with a tournament high 17 offloads has the chance of being the first player to win the World Cup in both rugby league and rugby union after triumphing with the All Blacks in 2020. I39。 2018 semifinal win over England, has been passed fit after a lowerleg injury, while Slater has been named at fullback but is still recovering from a knee injury aggravated against USA. Both sides boast 100% records heading into the encounter but Australia have not conceded a try since Josh Charnley39。已知基本結構如下圖所示,求系數(shù)項和自由項。 EI=常數(shù)。m5kN 10kN 2m2m4m 4m 參考答案: 10kN Δ1 Δ1=13i4i2i2i4i 1Mk11 基本體系 5kN 2 EIEIll/2l/2 PF 參考答案: 2iiΔ1 PF Δ1=18i2i4i 1Mk11 4i 基本體系 F1PPM8/lFP 8/lFP8/lFP 用位移法計算圖示剛架, 求出系數(shù)項及自由項。 作后彎矩圖如圖( f)所示。 圖( a)簡化一半剛架如圖( c)所示。桿件 EI 為常數(shù)。 作后彎矩圖如圖( c)所示。 llP PF 參考答案: 利用對稱性結構簡化為如圖( a)所示 。 作后彎矩圖如圖( d)所示。 1M 圖如圖( b)所示。mM ( 1 / 32 ) , EI=常數(shù)。 (2) 列力法方程 011111 ????? Px? (3) 作 1M 圖,見圖( b) 作 PM 圖,見圖( c) (4) 計算 ?1 ?1P EIEIEIEIM 325644413844211d s2111 ??????????? ? ??EIEIEIdEIMM SPP 311604420201022021111 ?????????????? ? ?321451 ?x ( kN) X11 0 k NX1= 14 m1M1 0 k N 2 0PM4 m mkN? ( a) ( b) ( c) (5) 作 M 圖 10 kN290 k N EI=常數(shù)。( ) 42.弱阻尼自由振動是一個衰減振動。( ) 40.干擾力只影響振動質(zhì)點振幅,不影響結構的自振頻率。 ( ) 38.反映結構動力特性的參數(shù)是振動質(zhì)點的振幅。( ) 2 E IE I E IE I E IPF PF E IE IE I ( a) ( b) 36.圖( a)對稱結構利用對稱性可簡化為圖( b)來計算。( √ ) 34.影響線的橫坐標是單位荷載的位置。 ( )Al1?PF 32.圖示結構 yDF 影響線的 AC 段縱標為零 。( ) 30.當 AB 桿件剛度系數(shù) iSAB 3? 時,桿件的 B 端為定向支座。( √ ) 28.力矩分配法適用于所有超靜定結構的計算。 ( √ ) 26.用力矩分配法計算結構時,匯交于每一結點各桿端分配系數(shù)總和為 1,則表明分配系數(shù)的計算無錯誤。( √ ) 24.位移法的基本結構不是唯一的。( √ ) 束上的反力。 ( ) ,虛設力狀態(tài)可以在力法的基本結構上設。( ) 靜定結構的內(nèi)力狀態(tài)與 剛度 有關 。( ) 16.圖示結構的超靜定次數(shù)是 n=3。() 14.基本附屬型結構的計算順序是:先計算附屬部分后計算基本部分。( √ ) 12. 靜定多跨梁中基本部分、附屬部分的劃分與所承受的荷載 無 關 。 (√ ) 專業(yè)好文檔 5 10. 在溫度變化或支座位移的作用下,靜定結構有內(nèi)力產(chǎn)生 。( ) PP 8. 依據(jù)靜力平衡條件可對靜定結構進行受力分析,這樣的分析結果是唯一正確的結果。( ) 6.在桁架結構中,桿件內(nèi)力不是只有軸力。 ( ) ql lA 4.圖示梁 AB 在所示荷載作用下 A截面的彎矩值為22ql 。( ) A1?PF ,按此力狀態(tài)及位移計算公式可求出 AB 兩點的相對線位移。( ) 85.無阻尼單自由體系的自由振動是簡諧振動,所以它是簡諧 荷載引起的。( √ ) 83.外界干擾力既不改變體系的自振頻率,也不改變振幅。( √ ) 81.在結構動力計算中,四質(zhì)點的振動體系,其振動自由度一定為 4。( ) 79.動力系數(shù) ? 總是大于 1 的。( ) E I= ∞ 77.圖示體系