a二端口網(wǎng)絡(luò)ppt課件(參考版)
2025-01-08 03:15本頁(yè)面
【正文】 164 二端口的轉(zhuǎn)移函數(shù) (傳遞函數(shù) ) )()()]()()()([)( 11102121111 2 sIsZsIsZsIsZsU I ??? ?)()()]()()()([)( 12102221212 2 sIsZsIsZsIsZsU I ??? ?)()()()(112112sZsZsUsU ?電壓轉(zhuǎn)移函數(shù)： BACK NEXT )()(1121SZSZ?)()(2221SYSY??)()()(12SUSUSH ?N U1(S) U2(S) I1(S) I2(S) )()(Y)()(Y)( 2221212 sUssUssI ??又因?yàn)椋?(Y)(Y)()(0)(2212122 sssUsUsI ??? ，則電壓轉(zhuǎn)移函數(shù)令BACK NEXT )()(1121sYsY?)()(2221sZsZ??0)(122)()()(?? sUsIsIsH電流轉(zhuǎn)移函數(shù)：N U1(S) U2(S) I1(S) I2(S) 同理可以求得其它轉(zhuǎn)移函數(shù)： )()()()(210)(122sYsUsIsHsU ?? ?轉(zhuǎn)移導(dǎo)納：)()()()(210)(122sZsIsUsHsI ?? ?轉(zhuǎn)移阻抗：BACK NEXT 2 單端接（端口 1電源無(wú)內(nèi)阻，端口 2接負(fù)載） N U1(S) U2(S) I1(S) I2(S) R 已知 Y參數(shù)求 )()()( 2SUSISHS????????)()()()()()()()()()(22212122121111SUSYSUSYSISUSYSUSYSIRSISU )()( 22 ??)(1)()()()(22212SRYSYSUSISHS ???)()(1 SUSU S?。( ?? UCC1I??BACK NEXT 若已知 Y參數(shù) ?????????22212122121111UYUYIUYUYI??????112212221122 U)(UYUYI ???? YY ????U 1 . U 2 . I 1 I 2 . Y 11 U 2 . Y 12 Y 21 U 1 . . Y 22 Ya Yb Yc ?? 11221 )( UYY?1U?2U+ + 1.I2.I?2.IBACK NEXT ?????????22212122121111IZIZUIZIZU??????等效電路為： . U 1 . I 1 . Z 11 Z 12 I 2 . U 2 . I 2 Z 22 Z 21 I 1 . 若已知 Z參數(shù) 其中 2112 ZZ ?BACK NEXT 等效電路不唯一 將此方程變換 ? ????????????1122122211222121111IZZIZIZUIZIZU????????????????22212122121111IZIZUIZIZU??????其中 ??????????22211222121111IZIZUIZIZU??????相當(dāng)于一互易二端口， 可求出其等效電路 BACK NEXT T型等效電路為： ? ?:21.12212.2.效電路為處串入一受控源。 其中 2112 YY ?將上述方程變換 ? ????????????1122122211222121111UYYUYUYIUYUYI????????????????22212122121111UYUYIUYUYI??????2I??BACK NEXT 其中 相當(dāng)于一互易二端口， 可求出其等效電路 (?型 )： (計(jì)算見前例 ) ?????????22211222121111UYUYIUYUYI39。 N 8V ic K R1 R1 R2 8V 解： ????????????????????????2211IU DCBAIU????2210212 RRRUUAI???????2021 12 RUICI ?? ????212211021 )(2 RRRRRRIUBU????? ???? ????BACK NEXT ? ??????????????????22122121212211)(RRRRRRRRRRRRRT比較系數(shù)得 R1=1?, R2=2? 1 ? 1 ? 2 ? 8V ic 三要素 516323/218)0( ????ci0)( ??ci )132( ?????Aei tc 43516 ?????
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