電大微積分初步形成性考核冊(cè)作業(yè)答案小抄參考資料【精編版(參考版)
2025-06-07 12:20本頁(yè)面
【正文】 t. Baumgartner still will free fall at a speed that would cause you and me to pass out, and no parachute is guaranteed to work higher than 25,000 feet (7,620 meters). cause there 。ll be traveling fast, so despite the distance, it will not be like diving into the deep end of a pool. It will be like he is diving into the shallow end. Skydiver preps for the big jump When he jumps, he is expected to reach the speed of sound 690 mph (1,110 kph) in less than 40 seconds. Like hitting the top of the water, he will begin to slow as he approaches the more dense air closer to Earth. But this will not be enough to stop him pletely. If he goes too fast or spins out of control, he has a stabilization parachute that can be deployed to slow him down. His team hopes it39。s actions. CSKA said they were surprised and disappointed by Toure39。s 21 win. Michel Platini, president of European football39。s Premier League match at Chelsea on Sunday. I am going to be at the match tomorrow and I have asked to meet Yaya Toure, he told BBC Sport. For me it39。s antiracism taskforce, is in London for the Football Association39。 we need the courage to do it. His ments came hours after Fifa vicepresident Jeffrey Webb also in London for the FA39。 證明： ??? ???? aaa a dxxfdxxfdxxf 00 )()()( 考慮積分 ??0 )(a dxxf，令 tx ?? ，則 dtdx ?? ，從而 ????? ??????????? aaaaa dxxfdttfdttfdttfdxxf 00000 )()()(])[()( 所 以 ??? ???? aaa a dxxfdxxfdxxf 00 )()()( ??? ?????? aaa dxxfxfdxxfdxxf000 )]()([)()( 16 If we don39。 解：由定積分的幾何意義知， xxaa d0 22? ?就等于圓 222 ayx ?? 在第Ⅰ象限的面積，即 圓 222 ayx ?? 面積的 41 ，因此 xxaa d0 22? ? 241 a?? 6． ???e1 2 d)1ln(dd xxx . 解： ???e1 2 d)1ln(dd xxx0 7． xxde0 2???= ． 解： xxde0 2???020 20 221l i m)2(l i m21l i m bxbb xbb xb exdedxe ????????? ?? ?? 21)1(lim21 2 ?????? bb e 8．微分方 程 1)0(, ??? yyy 的特解為 . 解：由 yy?? 得 ydxdy? ， dxydy?，兩邊同時(shí)積分，得 cxy ??ln 因?yàn)?1)0( ?y ，所以 c??01ln ，所以 0?c 13 從而 xy?ln ，因此微分方程 1)0(, ??? yyy 的特解為 xey? 9．微分方程 03 ??? yy 的通解為 . 解： 03 ??? yy ， 03 ?? ydxdy， 03 ?? dxydy， 13ln cxy ?? xcy 3ln 1 ?? ， xcey 31?? ，即 xc eey 31 ??? 所以微分方程 03 ??? yy 的通解為 xcey 3?? 10．微分方程 xyxyy s in4)( 7)4(3 ???? 的階數(shù)為 ． 解：微分方程 xyxyy s in4)( 7)4(3 ???? 的階數(shù)為 4 階 二、單項(xiàng)選擇題（每小題 2 分，共 20 分） 1．在切線斜率為 2x 的積分曲線族中，通過(guò)點(diǎn)（ 1, 4）的曲線為 （ A ）． A． y = x2 + 3 B． y = x2 + 4 C． 22 ??xy D． 12 ??xy 2．若 ? ?10 d)2( xkx= 2，則 k =（ A ）． A． 1 B． 1 C． 0 D． 21 3．下列定積分中積分值為 0 的是 （ A ）． A． xxx d2ee11???? B． xxx d2ee11???? C． xxx d)cos( 3?? ??? D． xxx d)sin( 2?? ??? 4．設(shè) )(xf 是連續(xù)的奇函數(shù)，則定積分 ??aa xxf d)(（ D ） A． ?0 d)(2 a xxf B． ?0 d)(a xxf C． ?a xxf0 d)( D． 0 5． ?? xxdsin22??（ D ）． A． 0 B． ? C． 2? D． 2 6．下列無(wú)窮積分收斂的是（ B ）． A． ???0 de xx B． ??? ?0 de xx C． ???1 d1 xx D． ???1 d1 xx 7．下列無(wú)窮積分收斂的是（ B ）． A． ? ??0 din xxs B． ? ?? ?0 2 de xx C． ???1 d1 xx D． ???1 d1 xx 8．下列微分方程中，（ D ）是線性微分方程． A． yyyx ???ln2 B． xxyyy e2 ??? C． yyxy e????? D． xyyxy x lnesin ????? 14 9．微分方程 0??y 的通解為（ C ）． A． Cxy? B． Cxy ?? C． Cy? D． 0?y 10．下列微分方程中為可分離變量方程的是 （ B ） A. yxxy ??dd； B. yxyxy ??dd； C. xxyxy sindd ??； D. )(dd xyxxy ?? 三、計(jì)算題（每小題 7 分，共 56 分） 1． xxx d)e1(e 22ln0 ?? 解： xxx d)e1(e 22ln0 ?? 319389)1(31)1()1(2ln0322ln0 ???????? ? xxx eede 2． xx xdln51e1? ? 解： xx xdln51e1? ? ?? ?????ee xdxxdx11 )ln51()ln51(51ln)ln51( 21)16(101)ln51(2151 12 ??????ex 3． xxexd10?
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