【正文】 2023年 3月 上午 11時 29分 :29March 24, 2023 ? 1業(yè)余生活要有意義，不要越軌。 11:29:3811:29:3811:29Friday, March 24, 2023 ? 1知人者智，自知者明。 上午 11時 29分 38秒 上午 11時 29分 11:29: ? 楊柳散和風，青山澹吾慮。 2023年 3月 24日星期五 上午 11時 29分 38秒 11:29: ? 1楚塞三湘接，荊門九派通。 11:29:3811:29:3811:293/24/2023 11:29:38 AM ? 1成功就是日復一日那一點點小小努力的積累。 2023年 3月 上午 11時 29分 :29March 24, 2023 ? 1行動出成果，工作出財富。 11:29:3811:29:3811:29Friday, March 24, 2023 ? 1乍見翻疑夢，相悲各問年。 ?) Example 4 A customer service manager wants to determine the process capability for his department. A primary performance index is the time taken to close a customer plaint. The goal for this index is to close a plaint within one calendar week. Performance over the last 400 plaints was reviewed. Example 4 Stat ? Quality Tools ? Capability Analysis (Weibull) Example 4 2 52 01 51 050U S LP r o c e s s C a p a b i l i t y f o r C o m p l a i n t C l o s u r eC a l c u l a t i o n s B a s e d o n E x p o n e n t i a l D i s t r i b u t i o n M o d e lP P M T o t a lP P M U S LP P M L S LP P M T o t a lP P M U S LP P M L S LP p kP P LP P UP pS c a l eS h a p eS a m p l e NM e a nL S LT a r g e tU S L1 2 2 9 7 0 . 8 01 2 2 9 7 0 . 8 0 * 7 5 0 0 0 . 0 0 7 5 0 0 0 . 0 0 *0 . 3 9 *0 . 3 9 *3 . 3 41 . 0 04 0 03 . 3 4 * *7 . 0 0E x p e c t e d L T P e r f o r m a n c eO b s e r v e d L T P e r f o r m a n c eO v e r a l l ( L T ) C a p a b i l i t yP r o c e s s D a t aExample 4A Stat ? Quality Tools ? Capability Sixpack (Weibull) Example 4A 4 0 03 0 02 0 01 0 002 41 680I n d i v i d u a l a n d M R C h a r tO b s e r .Individual ValueM e a n = 3 . 3 4U C L = 1 0 . 4 6L C L = 3 . 7 7 92 41 680Mov.RangeR = 2 . 6 7 7U C L = 8 . 7 4 6L C L = 04 0 03 9 03 8 0L a s t 2 5 O b s e r v a t i o n s9630O b s e r v a t i o n N u m b e rValues7O v e r a l l ( L T )S h a p e : 1 . 0 0S c a l e : 3 . 3 4P p : *P p k : 0 . 3 9C a p a b i l i t y P l o tP r o c e s s T o l e r a n c eS p e c i f i c a t i o n sIIII1 0 . 0 01 . 0 00 . 1 00 . 0 1W e i b u l l P r o b P l o t2 01 00C a p a b i l i t y H i s t o g r a mP r o c e s s C a p a b i l i t y f o r C o m p l a i n t C l o s u r eProcess Capability for Reject Rate For a Normal Distribution, the proportion of parts produced beyond a specification limit is ? ? ?)Z(F1USLZPr1USLZPrUSLXPr???????????????????????????Reject Rate Process Capability for Reject Rate Thus, for every reject rate there is an acpanying ZScore, where Recall that Hence ????3NSLPpk ????? LimitSpecScoreZ3ScoreZpk?Process Capability for Reject Rate Estimation of Ppk for Reject Rate ? Determine the longterm reject rate (p) ? Determine the inverse cumulative probability for p, using Calc ? Probability Distribution ? Normal ? ZScore is the magnitude of the returned value ? Ppk is onethird of the ZScore Example 5 A sales manager plans to assess the process capability of his telephone sales department’s handling of ining calls. The following data was collected over a period of 20 days: ? number of ining calls per day ? number of unanswered calls per days Example 5 Stat ? Quality Tools ? Capability Analysis (Binomial) Example 5 2 01 000 . 2 60 . 2 50 . 2 40 . 2 30 . 2 20 . 2 10 . 2 00 . 1 9S a m p l e N u m b e rProportionP = 0 . 2 2 6 4U C L = 0 . 2 5 5 5L C L = 0 . 1 9 7 32 01 02 3 . 52 2 . 52 1 . 5S a m p l e N u m b e r%Defective2 62 42 22 02 0 5 01 9 5 01 8 5 02 62 52 42 32 22 12 0%DefectiveS a m p l e S i z eP r o c e s s C a p a b i l i t y f o r T e l e p h o n e S a l e sS u m m a r y S t a t sC u m u l a t i v e % D e f e c t i v e D i s t o f % D e f e c t i v eP C h a r t R a t e o f D e f e c t i v e s( d e n o t e s 9 5 % C . I . )A v e r a g e P :% D e f e c t i v e :T a r g e t :P P M D e f . :P r o c e s s Z :0 . 2 2 6 4 2 72 2 . 6 4 302 2 6 4 2 70 . 7 5 1( 0 . 2 2 2 2 , 0 . 2 3 0 7 )( 2 2 . 2 2 , 2 3 . 0 7 )( 2 2 2 2 4 1 , 2 3 0 6 5 4 )( 0 . 7 3 7 , 0 . 7 6 5 )Ppk = Process Capability for Defect Rate Other applications, approximating a Poisson Distribution : ? error rates ? particle count ? chemical concentration Process Capability for Defect Rate Estimation of Ytp for Defect Rate ? Define size of an inspection unit ? Determine the longterm defects per unit (DPU) DPU = Total Defects ? Total Units ? Determine the throughput yield (Ytp) Ytp = exp{–DPU} Process Capability for Defect Rate Estimation of SigmaCapability for Defect Rate ? Determine the opportunities per unit ? Determine the longterm defects per opportunity (d) d = defects per unit ? opportunities per unit ? Determine the inverse cumulative probability for d, using Calc ? Probability Distribution ? Normal ? ZScore is the magnitude of the returned value ? SigmaCapability = ZScor