【摘要】11(3)解:212sec2yxxx????y=(1sin)sin(cos)cosxxxxx????sincoscos2xxxx???3(3)解一:??y=sinsincosxxxx???3(3)解二:22si
2025-07-24 06:07
【摘要】1.隱函數(shù)的導(dǎo)數(shù)隱函數(shù)即由方程0),(?yxF所確定的函數(shù)).(xfy?直接在方程0),(?yxF兩邊對x求導(dǎo)再解出,y?但應(yīng)注意F對變元y求導(dǎo)時,要利用復(fù)合求導(dǎo)法則.2.對數(shù)求導(dǎo)法當函數(shù)式較復(fù)雜(含乘、除、乘方、開方、冪指函數(shù)等)時,在方程兩邊取對數(shù),按隱函數(shù)的求
2025-07-24 04:24
【摘要】?.?條件.?.重點難點重點:利用導(dǎo)數(shù)知識求函數(shù)的極值難點:對極大、極小值概念的理解及求可導(dǎo)函數(shù)的極值的步驟觀察圖象中,點a和點b處的函數(shù)值與它們附近點的函數(shù)值有什么的大小關(guān)系?aboxy??xfy?一極值的定義?點a叫做函數(shù)y=f(x)的極小值點,
2025-07-26 19:48
【摘要】了解函數(shù)單調(diào)性和導(dǎo)數(shù)的關(guān)系/能利用導(dǎo)數(shù)研究函數(shù)的單調(diào)性,會求函數(shù)的單調(diào)區(qū)間/了解函數(shù)在某點取得極值的必要條件和充分條件/會用導(dǎo)數(shù)求函數(shù)的極大值、極小值/會求閉區(qū)間上函數(shù)的最大值、最小值/會利用導(dǎo)數(shù)解決某些實際問題導(dǎo)數(shù)的應(yīng)用1.函數(shù)在某區(qū)間上單調(diào)的充分條件一般地,設(shè)函數(shù)y=f(x)在某個區(qū)間內(nèi)有導(dǎo)數(shù),如果在這個區(qū)間內(nèi)y′
2025-09-20 15:55
【摘要】......導(dǎo)數(shù)中雙變量的函數(shù)構(gòu)造21.(12分)已知函數(shù)(). ?。?)若函數(shù)是單調(diào)函數(shù),求的取值范圍;(2)求證:當時,都有.21.解:(1)函數(shù)的定義域為,∵,∴,∵函數(shù)是單調(diào)函數(shù),∴或在上恒成立,①∵,∴,即,,
2025-05-16 03:43
【摘要】復(fù)合函數(shù)的導(dǎo)數(shù)練習(xí)題一、選擇題=的導(dǎo)數(shù)是A.B.C.-D.-=sin3(3x+)的導(dǎo)數(shù)為(3x+)cos(3x+)(3x+)cos(3x+)(3x+)D.-9sin2(3x+)cos(3x+)=cos(sinx)的導(dǎo)數(shù)為A.-[sin(si
2025-03-25 00:18