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: 0 ,1njfR ? 1, 2, ,jM? ???( ) ( ) ( )e x x d x???21( ) ( ) ( )M jjje x f x V x???????? 1( ) ( ) ( )M j jjx c x d? ? ?? ??? ??? ?? ?1 2 2 2( ) [ ( ) ( ) ] , , [ ( ) ( ) ] , , [ ( ) ( ) ]Lj j j j j j jx V x f x V x f x V x f x?? ? ? ? ? ? ? ? ? ? ??對(duì)于單個(gè)輸入模式,泛化誤差不等式: ?對(duì)于單個(gè)輸入模式,泛化誤差不等式: E E D??1( ) ( )M jjE e x p x d x?? ? ? 1 [ ( ) ]M j jjE c E d ??? ? ? 1, 2, ,jM? ???? ?1 , , , , Lj j j jE ?? ? ?? ??? ??? 2[ ( ) ( ) ] ( )j jjV x f x p x d x? ?? ??? 1, 2, 3, , L?? ? ???BACK 2020/6/28 6 模糊測(cè)度多樣性訓(xùn)練算法 ?該訓(xùn)練算法考慮了分類器的訓(xùn)練誤差和多樣性兩個(gè)參數(shù) 如果兩個(gè)參數(shù)之一的提高導(dǎo)致另一個(gè)參數(shù)的極度下降,那么我們就不對(duì)密度做任何調(diào)整。,DD?39。 BACK 返回 2020/6/28 13 400 600 800 1000 1200 1400 1600 180000 . 10 . 20 . 30 . 40 . 50 . 60 . 7Fi g u r e 1n u m b e r o f c y c l ecapacity of diversity error and accuracy increasing500 1000 1500 20xx 2500 3000 3500 4000 4500 500000 . 0 50 . 10 . 1 50 . 20 . 2 50 . 30 . 3 50 . 40 . 4 50 . 5Fi g u r e 2n u m b e r o f c y c l ecapacity of diversity error and accuracy increasing0 1000 20xx 3000 4000 5000 600000 . 0 50 . 10 . 1 50 . 20 . 2 50 . 30 . 3 50 . 40 . 4 50 . 5Fi g u r e 3n u m b e r o f c y c l ecapacity of diversity error and accuracy increasingBACK 2020/6/28 14 進(jìn)一步的工作 ?利用遺傳