微機計算機原理及接口技術(shù)實驗指導書帶程序-wenkub
2022-11-06 19:11:41 本頁面
【正文】 序 駐留內(nèi)存。 13 示例程序 實驗一 輸入輸出 data segment str db 39。 jl s4 cmp al,39。 mov ah,2 int 21h int 21h jmp s5 s2: cmp al,39。 jg s3 mov dl,39。 jl s4 cmp al,39。 15 mov ah,2 int 21h int 21h jmp s5 s4: mov dl,39。 ax,the number push bx push dx push si push cx mov bx,10 mov dx,0 r1: div bx add dl,30h mov si,offset printstr add si,cx dec si mov [si],dl mov dx,0 cmp ax,0 jz r2 loop r1 r2: pop cx mov si,offset printstr r3: mov ah,2 mov dl,[si] int 21h inc si loop r3 pop si pop dx pop bx ret printout endp 17 code ends end main 實驗四 循環(huán)程序（一） data segment printstr db 0,0,0,0,0 answer db ? data ends stackseg segment db 100 dup(?) stackseg ends code segment main proc far assume cs:code,ds:data,ss:stackseg start:mov ax,data mov ds,ax xor ax,ax mov cx,100 s1: add ax,cx dec cx jnz s1 mov cx,4 call printout mov ax,04c00h int 21h main endp printout proc near 。print the sorted array next8:lea di,buffer mov bl,20 next9:mov cx,3 mov ax,[di] call printout inc di inc di mov ah,2 mov dl,32 int 21h dec bl jnz next9 mov ax,04c00h int 21h main endp printout proc near 。,39。,39。,39。, 39。,39。,39。 data ends stackseg segment 21 db 100 dup(?) stackseg ends code segment assume cs:code,ds:data,ss:stackseg start:mov ax,data mov ds,ax 。139。039。039。display month mov dl,[bx] mov ah,2 int 21h mov dl,[bx+1] mov ah,2 int 21h mov dl,[bx+2] mov ah,2 int 21h mov dl,13 mov ah,2 int 21h mov dl,10 mov ah,2 int 21h jmp s1 err: mov dx,seg errmessage mov ds,dx mov dx,offset errmessage mov ah,9 int 21h s3: mov ax,04c00h int 21h code ends end start 實驗七 找最大數(shù) data segment printstr db 0,0,0,0,0 buffer dw 768,435,235,232,226,372,354,876,343,346 dw 542,785,234,235,654,322,557,379,753,654 data ends 23 stackseg segment db 100 dup(?) stackseg ends code segment main proc far assume cs:code,ds:data,ss:stackseg start:mov ax,data mov ds,ax mov si,offset buffer mov cx,19 mov bx,[si] s2: add si,2 cmp bx,[si] jae s3 mov bx,[si] s3: loop s2 mov cx,3 mov ax,bx call printout mov ax,04c00h int 21h main endp printout proc near 。 ax,the number push bx push dx push si push cx mov bx,10 26 mov dx,0 r1: div bx add dl,30h mov si,offset printstr add si,cx dec si mov [si],dl mov dx,0 cmp ax,0 jz r2 loop r1 r2: pop cx mov si,offset printstr
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