【正文】
浙江大學(xué)遠(yuǎn)程教育學(xué)院《工程力學(xué)與建筑結(jié)構(gòu)》課程作業(yè)姓名:學(xué) 號:年級:2013秋學(xué)習(xí)中心:湖州學(xué)習(xí)中心—————————————————————————————一、作圖題1.用力的平行四邊形法則求以下兩力的合力。 2.試畫出如圖所示小球的受力圖。(注意有二力桿時的畫法。) (b),試求桿內(nèi)的軸力并作出軸力圖。(1) (2)5.畫出圖示各梁的剪力圖和彎矩圖。 6.試作圖示剛架的M、Q、N圖。 7.試判斷圖示桿架中的零桿。一.計算題1. 桿AO和桿BO相互以鉸O相連接,兩桿的另一端均用鉸連接在墻上。鉸O處掛一個重物Q=50kN,如圖所示。試用解析法求桿AO和桿BO所受的力.解:以點(diǎn)O為研究對象,受力圖如圖所示:列平衡方式得:ΣFX=0 FBOFAOcos60186。=0ΣFY=0 FAOsin60186。=0求解上式,得FAO= (拉) FBO= 。解:受力分析,畫受力圖:由于AB桿上僅有一個力偶負(fù)載,故AB出的約束力組成一個力偶:受力圖如下。列平衡方式ΣM=0 FBXa=0 FB=Pa/a=PFA=FB=P。 解:取整個結(jié)構(gòu)為研究對象,畫受力圖。由ΣFX=0:5 4 FAX=0FAX=20KM由ΣMA=0:20(2+2)20 2 5 4 2+6FB=0FB=由ΣFY=0:FYA 20 20+FYB=0FAY=。 解:ΣMA=0得40*2+20*4*2Fby*4=0Fby=60KN( )ΣFX=0得FAX40=0FAX=40KN( )ΣFy=0得FAy20*4+60=0Fay=20KN( ) ,如橫截面的面積A1=200mm2,A2=300mm2,A3=400mm2,求各橫截面上的應(yīng)力.解:計算各段桿件橫截面上的軸力利用截面法求的階梯桿各段的軸力F1=10KNF2=10KN50KN=60KNF3=10KN50KN+20KN=40KN計算各段應(yīng)力A1段;A1=F1/A1=10*10179。/200Mpa=50MpaA2段;A2=F2/A2=60*10179。/300Mpa=200MpaA3段;A3=F3/A3=40*10179。/400Mpa=100Mpa,水平粱AB上受均布荷載q=10kN/m的作用,B端用圓鋼桿BC拉住,鋼桿的許用應(yīng)力[σ]=160MPa,試選擇鋼桿的直徑.解:求個點(diǎn)的約束反力,以整個構(gòu)架為研究對象,受力如圖所示:列平衡方式ΣMA=0得3*Fbccosa2*4q=0求解上式得:Fbc=(負(fù)號表示力的實(shí)際方向相反)確定鋼管面積[A]有強(qiáng)度推測Fbc/A≤[σ]得A=Fbc/[σ]=*10179。/160*10179。=(MM178。)確定鋼管直徑d由A=πd178。/4得d= ==取鋼桿的d為17mm。 解:確定截面形心C的位置 建立坐標(biāo)Oyz,將截面分為兩個矩形2,其面積及各自的形心縱坐標(biāo)分別為A1=5*20=100cm178。yc1=5+20/2=15cmA2=5*15=75cm178。Yc2=5/2=由形心計算公式,組合截面形心C的縱坐標(biāo)分Yc= = =求截面對形心軸Zc的慣性矩Iz根據(jù)組合公式有Izc=Izc(1)+Izc(2)由平移公式的:Izc(1)= Izc(2)= Izc=Izc(1)+Izc(2)8.用截面法求圖示各梁指定截面上的內(nèi)力。解:求支座反力。由于僅有Y軸荷載。故兩支座也僅有Y軸力。列平行方式ΣFy=0 FAP+FB=0ΣMA=0 FB*1+P*a=0解得FA= FB= 選A處11截面左段為研究對象以Q表示剪力,由平衡條件Fy=0可知由平衡方程確定剪力的大小、實(shí)際方向Fy=FA Q=0Q1=FA=由于11與A重合,又由平衡條件m1(F)=0可知M1=0選P處左段22截面為研究對象有平衡條件ΣFy=0可知由平衡方程確定剪力Q2Fy=FA Q2=0Q2=FA=由平衡條件m2(F)=0可知m2=Q2**選P處右段33截面為研究對象由平衡條件Fy=0可知由平衡方程確定剪力Q3Fy=FA * P Q3=0Q3= FA * P= *P= 由平衡條件m3(F)=0可知m3=Q3 * *,受均布荷栽作用,材料的容許應(yīng)力[σ]=10MPa,其高寬比為h:b=3:2,試確定此梁橫截面尺寸。解:求支座反力由ΣFX=0得FAX=0由ΣFy=0得FAy=ql=104=40KN由ΣM=0 M=1042=80 KN求最大剪力及彎矩Q=qx=104=40KN(0x4)M===104178。=80KN/m(0x4)求截面尺寸得 取280mmh==280=420 mm,由工字鋼20b制成,已知L=6m,P=30kN,q=6kN/m,材料的容許應(yīng)力[σ]=160MPa,[τ]=90MPa,試校核梁的強(qiáng)度.解:σ=156≤[σ]=160MP τ=≤[τ]=90MP 安全一、對以下各體系做幾何組成分析1.2.3.解:皆為幾何不變體系二、計算題1.用截面法計算圖示桁架中指定桿件的內(nèi)力。解: 2. 兩端鉸支壓桿,材料為Q235鋼,具有圖示四種截面形狀,103mm2,試比較它們的臨界力。其中d2=0.7d1。解:圓形:正方形:長方形:圓環(huán)形=1:::,截面尺寸(200*550),。求鋼筋截面面積As并繪出截面配筋圖。(資料:Ⅱ級安全級別γO=、一類環(huán)境條件c=25mm, 砼等級為C20,fc=10n/mm2,鋼筋等級Ⅱ級,fy=310n/mm2,ξb=,結(jié)構(gòu)系數(shù)γd=)。解:答案: As=1133mm2解題提示:取as=35mm, h0=550-35=515mm。 == ξb= ρ=ξfc/fy=10/310 = % >ρmin=%As=ρbh0=%200515=1133mm2,截面尺寸(200*450),。求鋼筋截面面積As并繪出截面配筋圖。(資料:Ⅱ級安全級別γO=、一類環(huán)境條件c=25mm, 砼等級為C25,鋼筋等級Ⅱ級,ξb=,結(jié)構(gòu)系數(shù)γd=)。解:答案: As=解題提示:(1)取as=60mm,則h0=450-60=390mm。(2)驗(yàn)算是否需要配雙筋: = 故須按雙筋截面配筋。 (3)取=,即=。=(4)=(200390+310)/310==300450mm, lo=,在使用期間承受永久荷載產(chǎn)生的軸向力標(biāo)準(zhǔn)值NGK=150kN,可變荷載產(chǎn)生的軸向力標(biāo)準(zhǔn)值NQK=200kN,偏心矩e0 =300mm。采用對稱配筋,試對該截面進(jìn)行配筋設(shè)計。(資料:γG=,γQ=,Ⅱ級安全級別γO=、持久設(shè)計狀況ψ =,一類環(huán)境條件c=25mm , 砼等級為C20, 鋼筋等級Ⅱ級,ξb=,結(jié)構(gòu)系數(shù)γd=)。解:As=765mm2解題提示:(1)資料:C20混凝土 ; Ⅱ級鋼筋 ;取, 則=450-40=410mm。(2)內(nèi)力計算:柱所承受的軸向壓力設(shè)計值 =(3)偏心距及偏心距增大系數(shù)的確定: /=4500/450=108,應(yīng)考慮縱向彎曲的影響。 =300mm=450/30=15mm,按實(shí)際偏心距=300mm計算。,?。?;由于/=1015,故取=1;= (4)判別大小偏壓: 壓區(qū)高度 = 所以按大偏心受壓構(gòu)件計算。(5)配筋計算:===765mm2 =125(英文版 ) easily blame, to prevent the broken window effect. 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To be good at learning, the Constitution and the code as morality, politics and brought to fruition。 to implement , do not want to, dare not, not with disciplinary ruler to supervision。 to discipline a ruler, often the control inspection, and consciously in the ideological red line to draw the row Ming Good accumulation is indeed the bottom line, so that the heart has fear, said to have quit, the line has ended. Attached: indifferent to heart, calmly to the table in our life, there are many unpredictable things will happen, some good, some bad things, we cannot control is powerless to stop, but with time, you will find in life so