gmat考試problemsolving復(fù)習(xí)資料-閱讀頁
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【正文】 3. 664!item!187。s gross profit on each crate of oranges (sold each orange for $)=5( per crate)+X 8=5+X, X=3 2. 455!item!187。000306 A grocery store purchased crates of 40 oranges each for $ per crate and then sold each orange for $. What was the store39。 PP Problem Solving1 (PS1) 完整詳解版 Practice Test 1 Problem Solving (196 Questions) 1. 409!item!187。058amp。s gross profit on each crate of oranges? (A) $ (B) $ (C) $ (D) $ (E) $ 【答案】 A 【思路】 revenue=cost+profit, 假設(shè) X為 the store39。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。s selling price, approximately what was the bond39。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。s daycare center, and a pair of children is to be selected to play a game. At most, how many different pairs are possible? (A) 100 (B) 90 (C) 50 (D) 45 (E) 25 【答案】 D 【思路】 C(10,2)= 10!8!2!=45 27. 3330!item!187。003295 38, 69, 22, 73, 31, 47, 13, 82 Which of the following numbers is greater than threefourths of the numbers but less than onefourth of the numbers in the list above? (A) 56 (B) 68 (C) 69 (D) 71 (E) 73 【答案】 D 【思路】將上述的 sequence由小到大重新排列 13,22,31,38,47,69,73,82 假設(shè)題目要求的 number為 X,X大於數(shù)列的 34 ,小於 數(shù)列的 14 數(shù)列共有 8個(gè)數(shù) , 34X8=6, 14X8=2 so, 69X73, 答案為 71(D) 28. 3377!item!187。003297 If xy = 1, what is the value of 2^[(x+y)^2] / 2^[(xy)^2] ? (A) 2 (B) 4 (C) 8 (D) 16 (E) 32 【答案】 D 【思路】根據(jù) r rssx xx ??,所以 2 2 2 2 2 2 22 2 2( 2 )( ) ( 2 ) 2 2 4()22 2222 x x y yx y x x y y x x y y x x y y x yxy ??? ? ? ? ? ? ? ?? ? ? ? xy=1,故 the value= 42 =16 29. 3426!item!187。003323 The value of the expression above is closest to which of the following? (A) (B) (C) (D) 1 (E) 10 30. 3528!item!187。003455 A furniture dealer purchased a desk for $150 and then set the selling price equal to the purchase price plus a markup that was 40 percent of the selling price. If the dealer sold the desk at the selling price, what was the amount of the dealer39。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。058amp。 4＝ 10 54. 6787!item!187。005232 An auction house charges a mission of 15 percent on the first $50,000 of the sale price of an item, plus 10 percent on the amount of the sale price in excess of $50,000. What was the sale price of a painting for which the auction house charged a total mission of $24,000 ? (A) $115,000 (B) $160,000 (C) $215,000 (D) $240,000 (E) $365,000 【答案】 C 【思路】 plus 10 percent on the amount of the sale price in excess of $50,000 超過 50000的部份收 10% 設(shè) the amount of the sale price 為 x 50000 15％＋ (x50000) (10％ )＝ 24000 X＝ 215000 55. 6892!item!187。005291 Which of the following inequalities has a solution set that, when graphed on the number line, is a single line segment of finite length? (A) X4 ≧ 1 (B) X3 ≦ 27 (C) X2 ≧ 16 (D) 2 ≦ |X| ≦ 5 (E) 2 ≦ 3X + 4 ≦ 6 56. 6998!item!187。005424 A small water pump would take 2 hours to fill an empty tank. A larger pump would take 1/2 hour to fill the same tank. How many hours would it take both pumps, working at their respective constant rates, to fill the empty tank if they began pumping at the same time? (A) 1/4 (B) 1/3 (C) 2/5 (D) 5/4 (E) 3/2 57. 7044!item!187。005427 If n is a multiple of 5 and ? ?2n p q? , where p and q are prime numbers, which of the following must rt be a multiple of 25 ? (A) 2p (B) 2q (C) pq (D) 22pq (E) 3pq 【答案】 D 【思路】 題目給的是 n的質(zhì)因式分解 因?yàn)?n為 5的乘數(shù) 那麼 n的質(zhì)因式中必定包含 5這個(gè)因子 所以有兩種可能 p=5或q=5 如果 p=5 q不一定 那麼 n可以被 25整除 因?yàn)檫@裡已經(jīng)有兩個(gè) 5的因子 但是如果 q=5 p不一定 此時(shí) 只有增加一個(gè)質(zhì)因子 p 才能保證為 25整除 [另解 ] 題目說 :p^2q=5k 這邊就要先推論一下 ,有兩種可能情形 : (1)p=5,k=pq (2)q=5,k=p^2 直接看答案 D (p^2)(q^2)=5kq (由題目推的 ) 再帶入剛剛的兩種情形 (1)5kq=5(pq)(q)=25q^2 (2)5kq=5(p^2)(5)=25p^2 所以只有 22pq 符合條件 !
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