現(xiàn)澆鋼筋混凝土樓板配筋設(shè)計(jì)計(jì)算書模板-在線瀏覽
2024-08-31 09:49本頁面
【正文】 = :塑性板 (上端/下端/左端/右端):固定/固定/固定/固定 結(jié)構(gòu)重要性系數(shù): γo = 塑性板β = 五、計(jì)算參數(shù): : Lo = 2700 mm : ho = has=12025=95 mm六、配筋計(jì)算(lx/ly=2700/4800= 所以按雙向板計(jì)算): 1) 確定X向板底彎矩 Mx = ζ((γG*ｑgk+γQ*ｑqk)*Lo2) = *(*+*)* = kN*m 2) 確定計(jì)算系數(shù) αs = γo*Mx/(α1*fc*b*ho*ho) = *106/(**1000*95*95) = 3) 計(jì)算相對(duì)受壓區(qū)高度 ξ = 1sqrt(12*αs) = 1sqrt(12*) = 4) 計(jì)算受拉鋼筋面積 As = α1*fc*b*ho*ξ/fy = **1000*95* = 98mm2 5) 驗(yàn)算最小配筋率 ρ = As/(b*h) = 98/(1000*120) = % ρρmin = % 不滿足最小配筋要求 所以取面積為As = ρmin*b*h = %*1000*120 = 240 mm2 采取方案8200, 實(shí)配面積251 mm2 1) 確定Y向板底彎矩 My = αMx = * = kN*m 2) 確定計(jì)算系數(shù) αs = γo*My/(α1*fc*b*ho*ho) = *106/(**1000*95*95) = 3) 計(jì)算相對(duì)受壓區(qū)高度 ξ = 1sqrt(12*αs) = 1sqrt(12*) = 4) 計(jì)算受拉鋼筋面積 As = α1*fc*b*ho*ξ/fy = **1000*95* = 31mm2 5) 驗(yàn)算最小配筋率 ρ = As/(b*h) = 31/(1000*120) = % ρρmin = % 不滿足最小配筋要求 所以取面積為As = ρmin*b*h = %*1000*120 = 240 mm2 采取方案8200, 實(shí)配面積251 mm2 1) 確定左邊支座彎矩 Mox = βMx = * = kN*m 2) 確定計(jì)算系數(shù) αs = γo*Mox/(α1*fc*b*ho*ho) = *106/(**1000*95*95) = 3) 計(jì)算相對(duì)受壓區(qū)高度 ξ = 1sqrt(12*αs) = 1sqrt(12*) = 4) 計(jì)算受拉鋼筋面積 As = α1*fc*b*ho*ξ/fy = **1000*95* = 178mm2 5) 驗(yàn)算最小配筋率 ρ = As/(b*h) = 178/(1000*120) = % ρρmin = % 不滿足最小配筋要求 所以取面積為As = ρmin*b*h = %*1000*120 = 240mm2 采取方案8200, 實(shí)配面積251 mm2 1) 確定右邊支座彎矩 Mox = βMx = * = kN*m 2) 確定計(jì)算系數(shù) αs = γo*Mox/(α1*fc*b*ho*ho) = *106/(**1000*95*95) = 3) 計(jì)算相對(duì)受壓區(qū)高度 ξ = 1sqrt(12*αs) = 1sqrt(12*) = 4) 計(jì)算受拉鋼筋面積 As = α1*fc*b*ho*ξ/fy = **1000*95* = 178mm2 5) 驗(yàn)算最小配筋率 ρ = As/(b*h) = 178/(1000*120) = % ρρmin = % 不滿足最小配筋要求 所以取面積為As = ρmin*b*h = %*1000*120
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