【正文】 s. aacbbxaacbbx2424 2221????????02 ??? cbxax6/2/2022 Chapter 5 Decision Making and Branching include main ( ) { float a, b, c, f。 printf ( a = )。a )。 scanf ( %f, amp。 printf ( c = )。c )。 if ( a == 0 amp。 b == 0 ) printf(There is no solution!\n)。 else { f = b * b 4 * a * c。 else printf (There are 2 real roots: %.2f, %.2f.\n, (b + sqrt(f))/2/a, (b sqrt(f))/2/a )。 printf ( Input a positive integer: )。n )。 n = n / 10。 long n = 1。 scanf ( %d, amp。 printf ( %d!=, m )。 m 。 } 6/2/2022 Chapter 6 Decision Making and Looping Write a program to pute the sum of the digits of a given integer number. 6/2/2022 Chapter 6 Decision Making and Looping main ( ) { long n。 printf ( Input a positive integer: )。n )。 n = n / 10。 } 6/2/2022 Chapter 6 Decision Making and Looping The numbers in the sequence 1 1 2 3 5 8 13 21 …… are called Fibonacci numbers. Write a program using a do...while loop to calculate and print the first m Fibonacci numbers. (Hint: After the first two numbers in the series, each number is the sum of the two preceding numbers.) 6/2/2022 Chapter 6 Decision Making and Looping main ( ) { long f1 = 1, f2 = 1, f = 1。 printf ( How many numbers do you want to output? )。m )。 while ( i = m ) { printf ( %12ld , f )。 f1 = f2。 if ( i % 4 == 0 ) printf ( \n )。 } } 6/2/2022 Chapter 6 Decision Making and Looping Rewrite the program of the Example using the for statement. 6/2/2022 Chapter 6 Decision Making and Looping main ( ) { int count, n。 printf ( Enter the values of x and n: )。x, amp。 for ( y = , count = 1。 count++ ) y = y * x 。 n = %d。 } 6/2/2022 Chapter 6 Decision Making and Looping Write a program to evaluate the following investment equation V = P(1+r)n and print the tables which would give the value of V for various bination of the following values of P, r and n. P: 1000, 2022, 3000, ……, 10,000 r: , , , ……, n: 1, 2, 3, ……, 8 (I change the value of n for format.) (Hint: P is the principal amount and V is the value of money at the end of n years. This equation can be recursively written as V=P(1+r) P=V That is, the value of money at the end of first year bees the principal amount for the next year and so on.) 6/2/2022 Chapter 6 Decision Making and Looping main ( ) { int n。 char ch。 p = 10000。 for ( n = 1。 n++ ) if ( n == 1 ) printf ( %d year, n )。 for ( r = 。 r = r + ) { pp = p。 for ( n = 1。 n++ ) { v = pp * ( 1 + r )。 printf(%,v)。 scanf ( %c, amp。 } } 6/2/2022 Chapter 6 Decision Making and Looping Write programs to print the following outputs using for loops. (a) 1 (b) ***** 22 **** 333 *** 4444 ** 55555 * 6/2/2022 Chapter 6 Decision Making and Looping main ( ) /* (a) */ { int i, j。 i = 5。 j = i。 printf ( \n )。 for ( i = 5。 i ) { for ( j = 1。 j++ ) printf ( )。 j = i。 printf ( \n )。 for ( i = 1。 i++ ) { printf ( Please input the age of person %d:, i )。age )。 count ++ 。 } 6/2/2022 Chapter 6 Decision Making and Looping Write a program to print a table of values of the function y = exp(x) for x varying from to in steps of . The table should appear as follows: Table for Y = EXP(X) ________________________________________________ x …… …… ________________________________________________ 6/2/2022 Chapter 6 Decision Making and Looping include main ( ) { double x = 0。 printf ( \nY = EXP(X)\n )。 i = 80。 printf (\n x\t)。 i = 9。 for ( i = 0。 i++ ) { printf ( \n\n%, i )。 j = 9。 printf ( \t%.2le, exp(x) )。 i = 80。 } 6/2/2022 Chapter 6 Decision Making and Looping Write a program that will read a positive integer and determine and print its binary equivalent. (Hint: The bits of the binary representation of an integer can be generated by repeatedly dividing the number and the successive quotients by 2 and saving the remainder, which is either 0 or 1, after each division.) 6/2/2022 Chapter 6 Decision Making and Looping main ( ) { long number, n。 printf ( Please input a positive number: )。number )。 while ( n 0) { n = n / 2。 } printf ( The equivalent binary of %ld is: , number )。 i = 1 。 for ( j =1。 j++ ) n = n / 2。 } } 6/2/2022 Chapter 6 Decision Making and Looping Write a program using for and if statement to display the capital letter S in a grid of 15 rows and 18 columns shown below. ******************* ******************* ******************* **** **** **** ******************* ******************* ******************* **** **** **** ******************* ******************* ******************* 6/2/2022 Chapter 6 Decision Making and Looping main ( ) { int i, j。 i = 15。 if ( i =4 amp。 i =6 ) printf ( **** )。amp。 else for ( j = 1。 j++ ) printf ( * )。s number e, that is used as the base of natural logarithms. Use the following formula. e = 1 + 1/1! + 1/2 ! + 1/3 ! + …… + 1/n! Use a suitable loop construct. The loop must terminate when the difference between two successive values of e is less than . 6/2/2022 Chapter 6 Decision Making and Looping define ERROR main ( ) { float e = 1, item。 long n。 do { for ( n = 1, i = 1。 i++ ) n = n * i。 e = e + item。 m++。 printf ( =%f\n, e )。 int n, i。 scanf ( %f, amp。 printf ( The rate of depreciation (per year)