【正文】
,c os:為參數(shù)設為參數(shù)設的參數(shù)方程求橢圓例ttyxyx2231149422??????? ?,c o s,c o s14993122???yx?? 得到代入橢圓方程把解? ? .s i n,s i nc o s ??? 2414 222 ????? yy 即所以的參數(shù)方程是橢圓所以可取的任意性由參數(shù)149222???yxy ,s i n, ??? ?為參數(shù)?.s in,c o s??23?yx? ? , 14492222??