高一物理牛頓運(yùn)動(dòng)定律綜合測(cè)試題試卷及參考答案(參考版)
2025-06-10 23:18本頁面
【正文】 FGθ14: F tanθ = ma a = gtanθ物體向右做勻加速；物體向左做勻減速GGGFN15．Μmg = ma a = μg = 1m/s2 t1 = v/a =1sx1 = at2/2 = 2m x2 = x—x1=20m—2m=18mt2 = x2/v = 9st = t1+t2 = 11sABvFfFGFfFN16：Fcosθ—μFN = 0 FN + Fsinθ—mg = 0μ = 1/3 a = μg = 10/3 m/s2x = 15mFTG1Ff1FNAG1+G2FFTFNBFf217:BAθFFTcosθ—μFNA = 0FNA + FTsinθ—G1 = 0 FT = F — μFNB — FTcosθ=0FTsinθ + FNB — G1 — G2 = 0 F = 18.CθABkx1 = mAgsinθkx2 = mBgsinθF— kx2 — mAgsinθ = mAaa = (F— mAgsinθ— mBgsinθ)/mAd = x1 + x2 = (mA + mB)gsinθ/k。只寫出最后答案的不能得分。CθAB高一物理牛頓運(yùn)動(dòng)定律綜合測(cè)試題參考答案題號(hào)12345678910答案CBCDAABBCACCDCF/m0a/ms2m、_1__mm 、打點(diǎn)計(jì)時(shí)器_、__天平___.12.（1） （2）小車和砝碼的總質(zhì)量的倒數(shù)
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