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微機原理、匯編與接口技術(shù)第二版朱定華版課后答案(參考版)

2025-06-03 18:02本頁面
  

【正文】 根據(jù)該方法編寫的程序段如下MOVK0ANDX0FFFFHJZBACKX0去BACKANDY0FFFFHJZBACKY0去BACKMOVK2MOVAXXXORAXYJSK24XY異號落在24象限MOVK1XY同號K1落在13象限K24CMPY0JNSBACKYgt0落在2象限ADDK2Ylt0落在4象限K2BACKret311stacksegmentstack′stack′dw32dup0stackendsdatasegmentIBUFDB909DUP026dataendscodesegmentbeginprocfarassumess:stackcs:codeds:datapushdsmovax0pushaxmovaxdatamovdsaxMOVDXOFFSETIBUFMOVAH10INT21HMOVCXMOVSI2AG:SHRIBUFSI1RCLDH1INCSILOOPAGMOVDLDHMOVCL4SHRDLCLCMPDL39HJBENAD71ADDDL7NAD71:MOVAH2INT21HMOVDLDHANDDL0FHCMPDL39HJBENAD72ADDDL727NAD72:MOVAH2INT21Hretbeginendpcodeendsendbegi312stacksegmentstack′stack′dw32dup0stackendsdatasegmentIBUFDB505DUP0dataendscodesegmentbeginprocfarassumess:stackcs:codeds:datapushdsmovax0pushaxmovaxdatamovdsaxMOVDXOFFSETIBUFMOVAH10INT21HMOVCLIBUF1MOVCH0MOVSIOFFSETIBUF2指向鍵入的第一個字符CMPBYTEPTRSI′??′判是否為負數(shù)PUSHF保護零標志供轉(zhuǎn)換之后再判別JNESININC正數(shù)跳轉(zhuǎn)去SININCINCSI越過“??”號指向數(shù)字28DECCX實際字符數(shù)少1“??”號SININC:MOVAL0開始將十進制數(shù)轉(zhuǎn)換為二進制數(shù)AGAIN:MOVAH10010a410…10a0MULAHANDBYTEPTRSI0FH將十進制數(shù)的ASCII碼轉(zhuǎn)換為BCD數(shù)ADDALSIINCSILOOPAGAINPOPF?;謴团袛嗍欠駷樨摂?shù)時的零標志ZFJNZNNEG非0即為正數(shù)則不求補NEGALMOVDLALMOVDHALMOVCL4SHRDLCLCMPDL39HJBENAD71ADDDL7NAD71:MOVAH2INT21HMOVDLDHANDDL0FHCMPDL39HJBENAD72ADDDL7NAD72:MOVAH2INT21Hretbeginendpcodeendsendbegi29313stacksegmentstack′stack′dw32dup0stackendsdatasegmentSWDW1234HOBUFDB5DUP0dataendscodesegmentbeginprocfarassumess:stackcs:codeds:datapushdsmovax0pushaxmovaxdatamovdsaxMOVBX5MOVOBUFBX′′MOVCX10MOVAXSWAG:MOVDX0ANDAXAXJZSCDIVCXADDDL30HDECBXMOVOBUFBXDLASCII碼送輸出數(shù)據(jù)區(qū)JMPAGSC:MOVDXOFFSETOBUFADDDXBXMOVAH930INT21Hretbeginendpcodeendsendbegin314stacksegmentstack′stack′dw32dup0stackendsdatasegmentARRAYWDW56??5680??80128??1280512……NEQU??ARRAYW/2PLUSDWNDUP0MINUSDWNDUP0ZERONDW0dataendscodesegmentstartprocfarassumess:stackcs:codeds:data31pushdssubaxaxpushxamovaxdatamovdsaxMOVCXNMOVBX0MOVSI0MOVDI0MOVZERON0AGAIN:MOVAXARRAYWBXADDBX2ANDAXAX根據(jù)AX的值置ZF、SFJZZERJSMINMOVPLUSSIAXADDSI2JMPCOMMIN:MOVMINUSDIAXADDDI2JMPCOMZER:INCZERONCOM:LOOPAGAINretstartendpcodeendsendstart315stacksegmentstack′stack′dw32dup032stackendsdatasegmentOBUFDB6DUP0datadedscodesegmentstartprocfarassumess:stackcs:codeds:datapushdssubaxaxpushaxmovaxdatamovdsaxMOVCX24??2MOVAX0第1項送AXMOVBX1第2項送BXAGAIN:ADDAXBX第i項和第i1項相加其和i2項在AX中XCHGAXBX第i2項和i1項互換LOOPAGAINMOVAXBX將第24項Fibonacci數(shù)送AXMOVDX0將第24項Fibonacci數(shù)擴展為32位二進制數(shù)MOVSI0建立OBUF變量數(shù)據(jù)區(qū)的位移指針MOVBX10000MOVCX4除法4次的計數(shù)器AGAIN1DIVBXADDAL30H將商轉(zhuǎn)換為ASCII碼MOVOBUFSIALINCSIMOVAXBX將除數(shù)送AXMOVBXDX將余數(shù)即下一
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