【正文】 取最不利管段1211121315171920，管網(wǎng)水頭損失為∑h=+++++++=最大時水泵揚程H1＝∑h+28+2+++2＝ 消防校核該市同一時間火災次數(shù)為三次，一次滅火用水量為100L/S，從安全和經濟角度考慮，失火點設在20節(jié)點及39節(jié)點處，消防時管網(wǎng)各節(jié)點的流量除39節(jié)點各附加100L/S的消防流量外，其余各節(jié)點的流量與最高時相同。節(jié)點水壓計算見下表：表16 節(jié)點水壓計算節(jié)點節(jié)點地形標高/m自由水壓/m水壓標高/m節(jié)點節(jié)點地形標高/m自由水壓/m水壓標高/m120 221 322423 524625 726827 928102911301231 1332 14331534163517361837 1938節(jié)點39為控制點3928 m，清水池最低水位2m，最低水位地面標高74m。（2）為可靠供水，從二級泵站到控制點之間選定幾條主要的平行干管線，這些平行干管中盡可能均勻的分配流量，并且滿足節(jié)點流量平衡的條件。 管網(wǎng)水力計算集中用水量主要為工廠的生產用水量和職工生活用水量或其他大用戶的用水量，當工人淋浴時間與最大時供水重合時淋浴用水也應該計入集中用水量，否則不計入集中用水量。清水池〉2500m179。Q31=222308900020%10%=1847120 L/d（2）根據(jù)《給排水快速設計手冊》，, L/ m2 計，由于面積太大澆灑面積按總面積的10%算Q32＝22308900030%10%= 1385340L/d（3）澆灑道路和綠化用水量Q3Q3= Q31+ Q32=1847120+1385340=3232460 L/d= m/d管網(wǎng)漏失水量按最高日用水量的11%計算?？側丝诘挠嬎悖?320=618400人，250=94100人。輸水管線走向應符合城市和工業(yè)企業(yè)規(guī)劃要求，沿現(xiàn)有道路鋪設，有利于施工和維護。城市的街區(qū)分布均勻，城市中各工業(yè)企業(yè)對水質無特殊要求。Foreword Water drains, water supply and drainage project is an important ponent of the project can be divided into drains and water supply pipeline project works two categories.Water pipeline project is on the upgrading of water, transmission, storage, distribution and regulation of science. Its most basic task is to ensure that the raw water source sent to the water treatment structures and water users with the water quality standard transmission and distribution to users. This task through the pump stations, pipelines, distribution mains network structure and regulation and other facilities to work together to achieve, and they formed a water pipeline project. Design and management is a basic requirement for at least the construction costs and management fees to ensure that the necessary water users and pressure to ensure water quality and safety, reduce leakage and achieve the required reliability.Outdoor urban water supply and drainage project is the construction of an important ponent of its main tasks is to provide adequate number of towns and meet certain water quality standards。②熟練城鎮(zhèn)給水排水工程系統(tǒng)的詳細計算和培養(yǎng)一定的理論分析和設計的能力。室外給水排水工程是城鎮(zhèn)建設的一個重要組成部分，其主要任務就是為城鎮(zhèn)提供足夠數(shù)量并符合一定水質標準的水；同時，把人們在生活、生產過程中使用后的污水匯集并輸送到適當?shù)攸c進行凈化處理，達到一定水質標準后，或重復使用，或灌溉農田，或排入水體。給水管道工程是論述水的提升，輸送，貯存，調節(jié)和分配的科學。其最基本的任務是保證水源的原料水送至水處理構筑物及符合用戶用水水質標準的水輸送和分配到用戶?！　? 室內給水排水工程的任務是將室外給水系統(tǒng)輸配的凈水組織供應到室內各個用水點，將用后的污水排除匯集到室外排水系統(tǒng)中去。提高方案的比較、技術經濟、環(huán)境、社會等諸方面的綜合分析和論證能力。 At the same time, people in the life of the production process to use the effluent water pooling and transported to a suitable site for purification of up to a certain quality standard, or repeated use, or irrigation or discharged into the water body. Indoor water supply and drainage project is the task of distribution of outdoor water supply system to supply water purification organizations in all indoor water, the sewage will be used to water to remove outdoor pool drainage systems.Does for the project class specialized student, the practice study and the design is our own knowledge acquisition and the experience best link. Moreover in the graduation project undergraduate course plan of instruction the essential link, after the undergraduate course stipulates the practical education which pletes the plete curriculum to have to carry on, the student through the graduation project, the synthesis utilizes the elementary theory, the basic skill which and deepens studies, trains the student independently to analyze and to solve the question ability, can enable the student through the graduation project to have:(1) Grasps the consult standard, the standard design atlas, the product catalog method, enhances the putation, the cartography and the pilation design explanation level, finishes an engineer39。因而采用統(tǒng)一給水系統(tǒng)。城市的輸水管和配水管采用鋼管（管徑）1000mm時和鑄鐵管。該城市為昆明市，隸屬云南省，查《室外排水設計規(guī)范》P61,人口50萬到100萬為大城市，云南省屬一區(qū)，則綜合生活用水定額為240~390 L/，本設計采用300L/%。Q4=（Q1+Q2+Q3） 11%= m/d管網(wǎng)漏失水量按最高日用水量的10%計算。應建成矩形較經濟，個數(shù)一般不少于兩個，并能單獨工作和分別放空。一區(qū)有工廠A，火車站 ∑q=+12=最高日最高時用水量Qh =qs=( Qh ∑q)/ ∑L=（）/39813= L/()Qh為最高日最大用水量L/s。（3）與干管線垂直的連接管，其作用主要是溝通平行干管之間的流量，有時起一些輸水作用，有時只是就近供水到用戶，平時流量不大，只有在干管損壞時 才轉輸較大的流量，因此連接管中可以較少的分配流量。, L/s，依此每條輸水管渠的管徑選為1700mm， 1000=，局部水頭損失按沿程水頭損失的10%計算，= 。消防平差結果見下表：=============================================================== 迭代次數(shù)=53 ================================================================== 環(huán)號= 1 閉合差= .000 管段號 管長 管徑 流速 流量 1000I 水頭損失 sq (米) (毫米) (米/秒) (升/秒) (米) 1 847 800 .99 .0025 2 1064 500 .98 .0144 3 800 300 .37 .86 .69 .0263 4 1137 500 .0162 sqtotal= .012 dq= .00 ================================================================== 環(huán)號= 2 閉合差= .000 管段號 管長 管徑 流速 流量 1000I 水頭損失 sq (米) (毫米) (米/秒) (升/秒) (米) 1 1030 500 .81 .0119 2 725 400 .76 .0165 3 1058 200 .24 .65 .69 .0930 4 1064 500 .98 .0144 sqtotal= .012 dq= .00 ================================================================== 環(huán)號= 3