【正文】 r unit ? Determine the inverse cumulative probability for d, using Calc ? Probability Distribution ? Normal ? ZScore is the magnitude of the returned value ? SigmaCapability = ZScore + Process Capability Analysis 64 Information, the way you want itExample 6 The process manager for a wire manufacturer is concerned about the effectiveness of the wire insulation process. Random lengths of electrical wiring are taken and tested for weak spots in their insulation by means of a test voltage. The number of weak spots and the length of each piece of wire are recorded. Process Capability Analysis 65 Information, the way you want itExample 6 Stat ? Quality Tools ? Capability Analysis (Poisson) Process Capability Analysis 66 Information, the way you want itExample 6 1 0 09 08 07 06 05 04 03 02 01 000 . 0 80 . 0 70 . 0 60 . 0 50 . 0 40 . 0 30 . 0 20 . 0 10 . 0 0S a m p l e N u m b e rSample CountU = 0 . 0 2 6 5 2U C L = 0 . 0 6 9 0 4L C L = 01 0 09 08 07 06 05 04 03 02 01 00 . 0 3 00 . 0 2 50 . 0 2 00 . 0 1 5S a m p l e N u m b e rDPU0 . 0 7 50 . 0 5 00 . 0 2 50 . 0 0 0T a r g e t1 5 01 4 01 3 01 2 01 1 01 0 00 . 0 80 . 0 70 . 0 60 . 0 50 . 0 40 . 0 30 . 0 20 . 0 10 . 0 0DPUS a m p l e S i z eP r o c e s s C a p a b i l i t y f o r W i r e I n s u l a t i o nS u m m a r y S t a t sC u m u l a t i v e D P U D i s t o f D P UU C h a r t D e f e c t R a t e( d e n o t e s 9 5 % C . I . )M e a n D P U :M i n D P U :M a x D P U :T a r g D P U :0 . 0 2 6 5 1 9 400 . 0 7 5 3 4 2 50( 0 . 0 2 3 7 3 0 9 , 0 . 0 2 9 5 4 5 5 )Defects per Unit = Throughput Yield = exp{–DPU} = exp{–} = . FirstTime Yield = 2 / 100 = Process Capability Analysis 67 Information, the way you want itExample 6 1 5 01 4 01 3 01 2 01 1 01 0 0 L e n g t hB o x p l o t o f L e n g t hDefine 1 Inspection Unit = 125 unit length of wire . Units = Length ? 125 Process Capability Analysis 68 Information, the way you want itExample 6A Stat ? Quality Tools ? Capability Analysis (Poisson) Process Capability Analysis 69 Information, the way you want itExample 6A 1 0 09 08 07 06 05 04 03 02 01 001 050S a m p l e N u m b e rSample CountU = 3 . 3 1 5U C L = 8 . 6 3 0L C L = 01 0 09 08 07 06 05 04 03 02 01 03 . 53 . 02 . 52 . 0S a m p l e N u m b e rDPU9630T a r g e t1 . 21 . 11 . 00 . 90 . 81 09876543210DPUS a m p l e S i z eP r o c e s s C a p a b i l i t y f o r W i r e I n s u l a t i o nS u m m a r y S t a t sC u m u l a t i v e D P U D i s t o f D P UU C h a r t D e f e c t R a t e( d e n o t e s 9 5 % C . I . )M e a n D P U :M i n D P U :M a x D P U :T a r g D P U :3 . 3 1 4 9 309 . 4 1 7 8 10( 2 . 9 6 6 3 7 , 3 . 6 9 3 1 9 )Defects per Unit = Throughput Yield = exp{–DPU} = exp{–} = . FirstTime Yield = 2 / 100 = Process Capability Analysis 70 Information, the way you want itExample 6B 1 0 09 08 07 06 05 04 03 02 01 001 050S a m p l e N u m b e rSample CountU = 3 . 3 1 5U C L = 8 . 6 3 0L C L = 01 0 09 08 07 06 05 04 03 02 01 03 . 53 . 02 . 52 . 0S a m p l e N u m b e rDPU9630T a r g e t1 . 21 . 11 . 00 . 90 . 81 09876543210DPUS a m p l e S i z eP r o c e s s C a p a b i l i t y f o r W i r e I n s u l a t i o nS u m m a r y S t a t sC u m u l a t i v e D P U D i s t o f D P UU C h a r t D e f e c t R a t e( d e n o t e s 9 5 % C . I . )M e a n D P U :M i n D P U :M a x D P U :T a r g D P U :3 . 3 1 4 9 309 . 4 1 7 8 10( 2 . 9 6 6 3 7 , 3 . 6 9 3 1 9 )Defects per Unit = Opportunities per Unit = 1 Defects per Opportunity = ZScore = ??? Process Capability Analysis 71 Information, the way you want itExample 6B 1 0 09 08 07 06 05 04 03 02 01 000 . 0 80 . 0 70 . 0 60 . 0 50 . 0 40 . 0 30 . 0 20 . 0 10 . 0 0S a m p l e N u m b e rSample CountU = 0 . 0 2 6 5 2U C L = 0 . 0 6 9 0 4L C L = 01 0 09 08 07 06 05 04 03 02 01 00 . 0 3 00 . 0 2 50 . 0 2 00 . 0 1 5S a m p l e N u m b e rDPU0 . 0 7 50 . 0 5 00 . 0 2 50 . 0 0 0T a r g e t1 5 01 4 01 3 01 2 01 1 01 0 00 . 0 80 . 0 70 . 0 60 . 0 50 . 0 40 . 0 30 . 0 20 . 0 10 . 0 0DPUS a m p l e S i z eP r o c e s s C a p a b i l i t y f o r W i r e I n s u l a t i o nS u m m a r y S t a t sC u m u l a t i v e D P U D i s t o f D P UU C h a r t D e f e c t R a t e( d e n o t e s 9 5 % C . I . )M e a n D P U :M i n D P U :M a x D P U :T a r g D P U :0 . 0 2 6 5 1 9 400 . 0 7 5 3 4 2 50( 0 . 0 2 3 7 3 0 9 , 0 . 0 2 9 5 4 5 5 )1 inspection unit = 1 unit length of wire Opportunities per Unit = 1 Defects per Opportunity = 329 ? 12,406 = ZScore = Abs{?–1()} = SigmaCapability = ZScore + = Process Capability Analysis 72 Information, the way you want itChoice of Six Sigma Metric Ins pec t ion Un it Un it Lengt h 1 2 5 Unit Le ng t hDefec t s 329 329Un its 1 2 ,4 0 6 9 9 .2 5Defec t s pe r Unit 0 .0 2 6 5 3 .3 1 4 9Th roug hp ut Y ie ld 0 .9 7 3 8 0 .0 3 6 3Defec t s pe r Oppo rtu nit y 0 .0 2 6 5 3 .3 1 4 9Si gma Cap a bili t y 3 .4 3 5 ???Process Capability Analysis 73 Information, the way you want it? 靜夜四無(wú)鄰，荒居舊業(yè)貧。 , January 20, 2023 ? 雨中黃葉樹(shù)，燈下白頭人。 20:16:1620:16:1620:161/20/2023 8:16:16 PM ? 1以我獨(dú)沈久，愧君相見(jiàn)頻。 :16:1620:16Ja