【正文】
queous vapor appendix table, the vapor pressure of aqueous vapor at 60℃ is 。 b) Humidity c) The humidity volume is: =(m179。humid air)/(kg dry air )So the density of humid air 112 A dryer is used to dry material from 5 percent moisture to percent moisture (wet basis). The production capacity of dryer is kg dry material/s. Hot air enters at 127℃ and water/kg dry air and leaves at 82℃.The temperature of the material in the inlet and outlet are 21℃ and 66℃, respectively. The specific heat of wet material is (kg℃)。If the heat loss of the dyer can be ignored, then calculate a) the consumption of the wet air. b) the temperature of the air leaving the dryer.Solution:The moisture content of the material (dry basis) isFrom the material balance, we have: From the enthalpy balance, we have:Where: kg water/kg dry air (3)From these, the ,L= wet air/s 113 A humid material is dried at a hours are required to reduce moisture content from 35 percent to 10 percent. The critical moisture content was found to be 15 percent and the equilibrium moisture 4 percent. If under the same drying conditions, it is required that the moisture content of the material drops to 0. 05 from that the rate of drying is proportional to the freemoisture content (X—X*), try to calculate how long will it take to dry the humid material. Solution: The drying time at constant rate stage is The drying time at falling rate stage is So the required drying time under the new condition is 114 A atmosphere parallelcounterflow dryer is to be designed to dry a humid material from moisture /kg dry material to moisture /kg dry material using hot air. The air enters at 135℃ and water/kg dry air, and leaves at 60℃. Assuming the air experienced equal enthalpy drying process. According to experiment, the rate of drying under the constantrate period can be represented by equation dx/dτ=30ΔH kg water /(kg dry material. H)。the rate of drying can be represented by equation dx/dτ= kg water/(kg dry material*h). Try to calculate how long should it takes to dry this material?Solution:Because the air experienced equal enthalpy drying process, the values of t1,H1,and t2 can be used to find the following values from the humidity chart: kg water/kg dry air kg water/kg dry air From material balance. Because the rates of drying in the meeting point between two stages are the same, so: Assume that the humidity of air is Ho corresponding to the critical moisture content of material Xo.Hence: (1) (2)From Eqs (1) and (2):Xo=Ho=1) The time of drying, in constant rate stage Separate variables and integrate: 2 The time of drying in falling rate stage 歡迎您的光臨,!希望您提出您寶貴的意見,你的意見是我進步的動力。贈語; 如果我們做與不做都會有人笑,如果做不好與做得好還會有人笑,那么我們索性就做得更好,來給人笑吧! 現(xiàn)在你不玩命的學,以后命玩你。我不知道年少輕狂,我只知道勝者為王。不要做金錢、權(quán)利的奴隸;應(yīng)學會做“金錢、權(quán)利”的主人。什么時候離光明最近?那就是你覺得黑暗太黑的時候。最值得欣賞的風景,是自己奮斗的足跡。壓力不是有人比你努力,而是那些比你牛幾倍的人依然比你努力。 參考