0086策略路由(編輯修改稿)
2025-03-23 07:59 本頁(yè)面
【文章內(nèi)容簡(jiǎn)介】 xthop RouterA(configroutemap) routemap access permit 30 RouterA(configroutemap) set default interface null0 RouterA(config) interface ether 0 RouterA(configif) ip address RouterA(configif) ip policy routemap access RouterA(config) interface serial 0 RouterA(configif) ip address RouterA(config) interface serial 1 RouterA(configif) ip address 24 策略路由的驗(yàn)證調(diào)試 ?顯示 IP策略應(yīng)用情況 routershow ip policy Interface Route map FastEther2 test ?Debug ip policy IP: s= (FastEther 1/1), d=(NULL), len=60, precedence=0, policy match RouteMap test, item = 10, permit IP: s= (FastEther 1/1), d=(FastEther 1/0), len=60, precedence=0, policy routed 25 顯示策略路由的配置 server_r1show routemap word routemap test, permit, sequence 10 Match clauses: ip address (accesslists): 1 Set clauses: default interface FastEther0 Policy routing matches: 42 packets, 2520 bytes routemap test, permit, sequence 20 Match clauses: ip address (accesslists): 2 Set clauses: ip nexthop Policy routing matches: 12 packets, 720 bytes ?顯示所有或指定路由映射的信息 26 提 綱 ?策略路由簡(jiǎn)介 ?策略路由的實(shí)現(xiàn)原理 ?策略路由的規(guī)劃設(shè)計(jì) ?策略路由部署應(yīng)用案例 27 策略路由部署應(yīng)用案例一 ?網(wǎng)絡(luò)拓?fù)? G1/1 G1/2 G1/3 s8610 用戶使用教育網(wǎng)地址 A用戶 B用戶 rg3760 28 策略路由部署應(yīng)用案例一 ?用戶需求 OICQ應(yīng)用全走電信出口 全部用戶 (A用戶 ) 非教育網(wǎng)流量走電信 (B用戶 ) 29 策略路由部署應(yīng)用案例一 ?如何實(shí)現(xiàn)？ routemap test permit 10 match ip address 103 set ip nexthop routemap test permit 20 match ip address 105 set ip nexthop ip accesslist extended 103 10 permit tcp any any eq 8000 20 permit udp any any eq 8000 //OICQ端口 ip accesslist extended 105 10 permit ip any 20 permit ip any 省略 … //.
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