【摘要】導(dǎo)數(shù)---常見(jiàn)題型例2、已知P為拋物線y=x2上任意一點(diǎn),則當(dāng)點(diǎn)P到直線x+y+2=0的距離最小時(shí),求點(diǎn)P到拋物線準(zhǔn)線的距離。例1、(1)求過(guò)點(diǎn)(1,1)且與曲線y=相切的直線方程。(2)求過(guò)點(diǎn)(2,0)且與曲線y=相切的直線方程。一、導(dǎo)數(shù)的幾何意義:——切線的斜
2024-11-09 02:26
【摘要】參變量函數(shù)的導(dǎo)數(shù)一、由參數(shù)方程所確定的函數(shù)的導(dǎo)數(shù).,)()(定的函數(shù)稱此為由參數(shù)方程所確間的函數(shù)關(guān)系與確定若參數(shù)方程xytytx???????例如?????,,22tytx2xt?消去參數(shù)22)2(xty???42x?xy21???
2025-07-18 14:25
【摘要】.導(dǎo)數(shù)的運(yùn)算幾個(gè)常用函數(shù)的導(dǎo)數(shù)1.導(dǎo)數(shù)的幾何意義是什么?????00.nnnnfxfxPPkxx???割線的斜率是????????000'00,.,.lim.xPPkPTfxxxkf
2024-12-08 07:42
【摘要】11(3)解:212sec2yxxx????y=(1sin)sin(cos)cosxxxxx????sincoscos2xxxx???3(3)解一:??y=sinsincosxxxx???3(3)解二:22si
2025-07-24 06:07
【摘要】1.隱函數(shù)的導(dǎo)數(shù)隱函數(shù)即由方程0),(?yxF所確定的函數(shù)).(xfy?直接在方程0),(?yxF兩邊對(duì)x求導(dǎo)再解出,y?但應(yīng)注意F對(duì)變?cè)獃求導(dǎo)時(shí),要利用復(fù)合求導(dǎo)法則.2.對(duì)數(shù)求導(dǎo)法當(dāng)函數(shù)式較復(fù)雜(含乘、除、乘方、開(kāi)方、冪指函數(shù)等)時(shí),在方程兩邊取對(duì)數(shù),按隱函數(shù)的求
2025-07-24 04:24
【摘要】?.?條件.?.重點(diǎn)難點(diǎn)重點(diǎn):利用導(dǎo)數(shù)知識(shí)求函數(shù)的極值難點(diǎn):對(duì)極大、極小值概念的理解及求可導(dǎo)函數(shù)的極值的步驟觀察圖象中,點(diǎn)a和點(diǎn)b處的函數(shù)值與它們附近點(diǎn)的函數(shù)值有什么的大小關(guān)系?aboxy??xfy?一極值的定義?點(diǎn)a叫做函數(shù)y=f(x)的極小值點(diǎn),
2025-07-26 19:48
【摘要】了解函數(shù)單調(diào)性和導(dǎo)數(shù)的關(guān)系/能利用導(dǎo)數(shù)研究函數(shù)的單調(diào)性,會(huì)求函數(shù)的單調(diào)區(qū)間/了解函數(shù)在某點(diǎn)取得極值的必要條件和充分條件/會(huì)用導(dǎo)數(shù)求函數(shù)的極大值、極小值/會(huì)求閉區(qū)間上函數(shù)的最大值、最小值/會(huì)利用導(dǎo)數(shù)解決某些實(shí)際問(wèn)題導(dǎo)數(shù)的應(yīng)用1.函數(shù)在某區(qū)間上單調(diào)的充分條件一般地,設(shè)函數(shù)y=f(x)在某個(gè)區(qū)間內(nèi)有導(dǎo)數(shù),如果在這個(gè)區(qū)間內(nèi)y′
2024-09-29 15:55
【摘要】......導(dǎo)數(shù)中雙變量的函數(shù)構(gòu)造21.(12分)已知函數(shù)(). (1)若函數(shù)是單調(diào)函數(shù),求的取值范圍;(2)求證:當(dāng)時(shí),都有.21.解:(1)函數(shù)的定義域?yàn)?,∵,∴,∵函?shù)是單調(diào)函數(shù),∴或在上恒成立,①∵,∴,即,,
2025-05-16 03:43
【摘要】復(fù)合函數(shù)的導(dǎo)數(shù)練習(xí)題一、選擇題=的導(dǎo)數(shù)是A.B.C.-D.-=sin3(3x+)的導(dǎo)數(shù)為(3x+)cos(3x+)(3x+)cos(3x+)(3x+)D.-9sin2(3x+)cos(3x+)=cos(sinx)的導(dǎo)數(shù)為A.-[sin(si
2025-03-25 00:18