word版可編輯-eda課程設(shè)計(jì)搶答器精心整理doc(存儲(chǔ)版)
【正文】 BEGINPROCESS(clk)BEGINIF (clk39。LIBRARY IEEE。temp=not temp。 clk100:out std_logic )。 WHEN 1001=dout=0010000。 WHEN 0001=dout=1111001。 end process。039。 end。 （三）報(bào)警模塊1. VHDL源程序library ieee。139。039。co=39。 elsif clk139。 ta,tb:buffer std_logic_vector(3 downto 0))。 end if。warm=st(0) or st(1) or st(2) or st(3)。139。 ) then st(2)=39。 or st(2)=39。139。 end if 。)and not( st(1)=39。st=0000。 light:buffer std_logic_vector(3 downto 0)。 分頻模塊：在這個(gè)模塊中主要實(shí)現(xiàn)搶答過程中所需的時(shí)鐘信號(hào)。4. 搶答器具有定時(shí)搶答功能，且一次搶答的時(shí)間由主持人設(shè)定（如20秒）5. 如果定時(shí)時(shí)間已到，無人搶答，本次搶答無效，系統(tǒng)報(bào)警并禁止搶答，定時(shí)顯示器上顯示20。若搶答時(shí)間內(nèi)無人搶答，則報(bào)警燈亮。關(guān)鍵詞：搶答鑒別 封鎖 計(jì)數(shù) 報(bào)警Abstract Responder is the answer for the quiz participants to answer in the design when a priority decision circuit, and the race can be divided into several groups, answer in each group on the host issues raised in the shortest possible time to make judgments , and press the answer in answer key. After pressing the button when the first person, then the display shows the number of the group, the corresponding lights, while other groups will be key circuit block, it does not work. If the answer in time, no answer in, the alarm lights. Answering questions, all the keys from the host to restore and restart the next round of the Responder. So to plete the answering device logic functions, the circuit should include Responder id
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