【正文】
ken into account for the calculation, the pumps alternate between duty and standby position with each running cycle. ?當(dāng)有效容積計(jì)算時(shí)只考慮一臺(tái)泵,雙泵按運(yùn)行周期交替運(yùn)行 ?The pumps are calculated for the peak flow ?水泵流量按照峰值流量計(jì)算 ?In case of very small ining flow, the velocity in the raising main must be high enough to prevent sedimentation. ?當(dāng)流量非常小時(shí),上升管的流速必須足夠大以避免沉淀 2 pumps in alternating operation where Qin QPump 當(dāng) Qin QPump, 2臺(tái)泵交替運(yùn)行 ?Pump A ?Pump B TP TS TP TS A A B ?2 – Calculating the effective volume – theory 有效容積計(jì)算-原理 m axE f f 4 ZQV p??G r u n d f o s F L O W T H I N K I N G16 2 pumps in alternating operation where Qin QPump 當(dāng) Qin QPump, 2臺(tái)泵交替運(yùn)行 ?Pump A ?Pump B TP TS TP A A B B A TS TP Note : 說明: ?If the ining flow exceed the capacity of the duty pump, the pump in standby position will start and 2 pumps are operating in parallel. ?如果入流流量超過工作水泵流量,備用水泵啟動(dòng), 雙泵并聯(lián)運(yùn)行 ? the pumps can be calculated for the ining flow≤peak flow. If one pump fails, the wastewater level in the pit can raise. ?可以按照入流流量 ≤峰值流量計(jì)算水泵流量,如果 一臺(tái)泵故障,允許泵站水位升高 ?2 – Calculating the effective volume – theory 有效容積計(jì)算-原理 m axE f f 4 ZQV p??For two pumps in alternating operation 對于雙泵交替運(yùn)行 G r u n d f o s F L O W T H I N K I N G17 Pumping stations with more than two pumps : 超過兩臺(tái)泵的泵站 ?The effective volume can be reduced when the pumps are working in parallel and assume alternately the position of duty and standby with each running cycle : ?水泵并聯(lián)運(yùn)行,按運(yùn)行周期交替運(yùn)行,有效容積減小 n = number of pumps excluding the spare pump 除備用泵以外的水泵數(shù)量 ?2 Effective Volume 有效容積 nZQV p??? m a xE f f 4 G r u n d f o s F L O W T H I N K I N G18 2 Effective Volume 有效容積 ? 傳統(tǒng)泵站計(jì)算方法-給水排水設(shè)計(jì)手冊(第五冊)-城鎮(zhèn)排水 G r u n d f o s F L O W T H I N K I N G19 2 Effective Volume 有效容積 ? 傳統(tǒng)泵站計(jì)算方法-給水排水設(shè)計(jì)手冊(第五冊)-城鎮(zhèn)排水 G r u n d f o s F L O W T H I N K I N G20 Exercice 練習(xí) ?Qp = 52,8 l/s ?2 pumps in alternating operation ?雙泵交替運(yùn)行 ?Circular tank : diameter 2300 mm ?圓形池:直徑 2300mm Information given: 已知信息 ?The effective volume Veff ?有效容積 Veff Calculate: 計(jì)算 G r u n d f o s F L O W T H I N K I N G21 Correction 正確的計(jì)算 Circular tank : diameter 2300 mm, R=1,15 m 圓形池:直徑 2300mm,R= Qin = 52,8 l/s is equal to 190 m3/h Qin = 52,8 l/s 等于 190 m3/h 3m a xm75,4104 1904 ????? ZQV pe f f e c t i v em14,115,1 75,4 22 ????? ??rVH e f f e c t i v ee f f e c t i v er Veffective Heffective G r u n d f o s F L O W T H I N K I