泵站設(shè)計關(guān)鍵ppt課件(存儲版)
【正文】 ken into account for the calculation, the pumps alternate between duty and standby position with each running cycle. ?當(dāng)有效容積計算時只考慮一臺泵，雙泵按運行周期交替運行 ?The pumps are calculated for the peak flow ?水泵流量按照峰值流量計算 ?In case of very small ining flow, the velocity in the raising main must be high enough to prevent sedimentation. ?當(dāng)流量非常小時，上升管的流速必須足夠大以避免沉淀 2 pumps in alternating operation where Qin QPump 當(dāng) Qin QPump， 2臺泵交替運行 ?Pump A ?Pump B TP TS TP TS A A B ?2 – Calculating the effective volume – theory 有效容積計算－原理 m axE f f 4 ZQV p??G r u n d f o s F L O W T H I N K I N G16 2 pumps in alternating operation where Qin QPump 當(dāng) Qin QPump， 2臺泵交替運行 ?Pump A ?Pump B TP TS TP A A B B A TS TP Note : 說明： ?If the ining flow exceed the capacity of the duty pump, the pump in standby position will start and 2 pumps are operating in parallel. ?如果入流流量超過工作水泵流量，備用水泵啟動， 雙泵并聯(lián)運行 ? the pumps can be calculated for the ining flow≤peak flow. If one pump fails, the wastewater level in the pit can raise. ?可以按照入流流量 ≤峰值流量計算水泵流量，如果 一臺泵故障，允許泵站水位升高 ?2 – Calculating the effective volume – theory 有效容積計算－原理 m axE f f 4 ZQV p??For two pumps in alternating operation 對于雙泵交替運行 G r u n d f o s F L O W T H I N K I N G17 Pumping stations with more than two pumps : 超過兩臺泵的泵站 ?The effective volume can be reduced when the pumps are working in parallel and assume alternately the position of duty and standby with each running cycle : ?水泵并聯(lián)運行，按運行周期交替運行，有效容積減小 n = number of pumps excluding the spare pump 除備用泵以外的水泵數(shù)量 ?2 Effective Volume 有效容積 nZQV p??? m a xE f f 4 G r u n d f o s F L O W T H I N K I N G18 2 Effective Volume 有效容積 ? 傳統(tǒng)泵站計算方法－給水排水設(shè)計手冊（第五冊）－城鎮(zhèn)排水 G r u n d f o s F L O W T H I N K I N G19 2 Effective Volume 有效容積 ? 傳統(tǒng)泵站計算方法－給水排水設(shè)計手冊（第五冊）－城鎮(zhèn)排水 G r u n d f o s F L O W T H I N K I N G20 Exercice 練習(xí) ?Qp = 52,8 l/s ?2 pumps in alternating operation ?雙泵交替運行 ?Circular tank : diameter 2300 mm ?圓形池：直徑 2300mm Information given: 已知信息 ?The effective volume Veff ?有效容積 Veff Calculate: 計算 G r u n d f o s F L O W T H I N K I N G21 Correction 正確的計算 Circular tank : diameter 2300 mm, R=1,15 m 圓形池：直徑 2300mm,R= Qin = 52,8 l/s is equal to 190 m3/h Qin = 52,8 l/s 等于 190 m3/h 3m a xm75,4104 1904 ????? ZQV pe f f e c t i v em14,115,1 75,4 22 ????? ??rVH e f f e c t i v ee f f e c t i v er Veffective Heffective G r u n d f o s F L O W T H I N K I
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