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【正文】 EDF是按如下方針制定其操作經(jīng)驗(yàn)反饋系統(tǒng)的:1 系統(tǒng)地收集盡可能多的數(shù)據(jù)資料,盡可能廣泛地交流收集到的數(shù)據(jù),特別是在EDF范圍內(nèi);2 在數(shù)據(jù)分析過程中,要盡可能地讓設(shè)計(jì)人員,運(yùn)行人員,制造廠商和安全機(jī)構(gòu)一起參與;3 吸取經(jīng)驗(yàn),這不僅有益于那些正在計(jì)劃和建設(shè)中的機(jī)組,而且有益于那些目前正在運(yùn)行的機(jī)組。 包括公共汽車,自動(dòng)過載電流設(shè)備和有或沒有為光、熱或者功率電路控制的開關(guān); 核電的安全,但只有在電廠真正進(jìn)入運(yùn)行階段,才有可能在各方面看到其核安全狀況,如:由于其設(shè)計(jì)缺陷出現(xiàn)的事故危險(xiǎn) 質(zhì)量不佳或運(yùn)行故障。 所有這一類建筑內(nèi)部的分布式系統(tǒng),不管他們大或小,必須符合一些基本要求:1. 安全性 a. 電擊的保護(hù) b. 對(duì)導(dǎo)體物理損傷的保護(hù) c. 對(duì)超載保護(hù) d. 對(duì)惡劣環(huán)境的保護(hù) 2. 導(dǎo)體的電壓降 它不應(yīng)該超出1或2% 3. 估計(jì)壽命 分布式系統(tǒng)應(yīng)該持續(xù)最小限度于50年 4. 經(jīng)濟(jì)性 電力設(shè)施的費(fèi)用應(yīng)該是在考慮到當(dāng)前一般標(biāo)準(zhǔn)的最小值。 ,問它在無需超出溫度極限的情況下運(yùn)行多久? 解答 = =7 =7 2000 =7 t = 例子262___________________________________________ 。 在導(dǎo)體上引起的熱 ,在功率一定的情況下我們可以計(jì)算導(dǎo)體上升的溫度差: 因此由 得出 因而斷定一個(gè)導(dǎo)體的溫度上升取決于因素。電流被產(chǎn)生,并且產(chǎn)生了可以控制CB開關(guān)的電壓?;蚣僭O(shè)1個(gè)120V的電爐掉入游泳池。發(fā)熱設(shè)備和聯(lián)絡(luò)裝置將導(dǎo)致電流流入在水池中的危害,即使電路的外殼被安全地接地,現(xiàn)在已經(jīng)發(fā)展為當(dāng)這樣的事件發(fā)生時(shí),設(shè)備的電源將被切斷。 由于5 mA不平衡狀態(tài)只必須被檢測(cè)出,變壓器的核心一定是非常有滲透性的在低通量密度。 眾所周知:高溫會(huì)破壞包裹在導(dǎo)體表面的絕緣。 如果它最初的溫度是50,計(jì)算以下: (銅熔化在1083) ,需要熔化導(dǎo)線的時(shí)間 解答 =197 A =197 30 t=因此,保險(xiǎn)絲可能在220ms后被熔斷。 標(biāo)準(zhǔn)由全國(guó)電子代碼規(guī)定,并且電子設(shè)施在它可以被放入服務(wù)之前必須由審查員批準(zhǔn)。保持安全水平為了保持安全水平,首先必須遵守設(shè)計(jì)所規(guī)定的運(yùn)行限制。 Groundfault circuit breakerThe grounding methods we have covered so far are usually adequate,but further safety measures are needed in some foe example , that a person sticks his finger into a lamp socket ().Although the metal enclosure is securely grounded, the person will still receive a painful shock. Or suppose a 120 V eletric toster tumbles into a swimming pool. The heating elements and contacts will produce a hazardos leakage current throughout the pool ,ven if the frame of the toaster is securely grounded. Devices have been developed that will cut the source of power as soon as such accidents occur. These groundfault circuit breaker will typically trip in 25 ms if the leakage current exceeds 5 mA. How do these protective devices operate ? A small current transformer surrounds the live and neutral wires as shown in . The secondary is connected to a sensitive electronic detetor that can trigged a circuit breaker CB that is in series with the 120 V line. Under normal conditions the current Iin the line conductor is exactly equal to thecurrent Iin the neutral ,and so the net current (II) flowing through the hole in the toroidal core is zero. Consequently, no flux is produced in the core, the induced voltage E is zero, and breaker CB does not trip. Suppose now that a fault current I leaks directly from the live wire to ground . This could happen if someone touched a live terminal (). A fault current I would also be produced if the insul
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