機(jī)床數(shù)控課設(shè)-插補(bǔ)原理及流程圖設(shè)計(jì)-免費(fèi)閱讀
【正文】 ************第４象限插補(bǔ) i = 0 j = 0 i1 = 0 j1 = 0 f = 0 If count = n Then For m = 1 To count Step 1 If f = 0 Then i1 = i + L (i + x0, j + y0)(i1 + x0, j1 + y0), RGB(255, 0, 0) i = i1 j = j1 f = f Abs(ye) ElseIf f 0 Then j1 = j L (i + x0, j + y0)(i1 + x0, j1 + y0), RGB(255, 0, 0) i = i1 j = j1 f = f + Abs(xe) End If Next m Else: count = 0 End If 圓弧 Private Sub LXddashun4(ByVal qx, ByVal qy, ByVal zx, ByVal zy, ByVal r, ByVal L, a, b, ByVal n, u) i = qx 39。*************Ｙ負(fù)向 i = 0 j = 0 i1 = 0 j1 = 0 If count = n Then For a = 1 To count j1 = j L (i + x0, j + y0)(i1 + x0, j1 + y0), RGB(255, 0, 0) j = j1 Next a Else: count = 0 End If End If flag1 = 1 End If If ye = 0 Then 39。*********************** 2象限 i = 0 j = 0 i1 = 0 j1 = 0 f = 0 For m = 1 To n Step 1 If f = 0 Then i1 = i L (i + x0, j + y0)(i1 + x0, j1 + y0), RGB(255, 0, 0) i = i1 j = j1 f = f Abs(ye) ElseIf f 0 Then j1 = j + L (i + x0, j + y0)(i1 + x0, j1 + y0), RGB(255, 0, 0) i = i1 j = j1 f = f + Abs(xe) End If Next m ElseIf xe 0 And ye 0 Then 39。*******終點(diǎn)判別 flag1 = 0 If xe = 0 Then 39。 （ 2） 了解逐點(diǎn)比較法和 DDA 法插補(bǔ)直線和圓弧的基本 原理。 插補(bǔ)（ interpolation）定義：機(jī)床數(shù)控系統(tǒng)依照一定方法確定刀具運(yùn)動(dòng)軌跡的過程。 二、設(shè)計(jì)目的 課設(shè)題目： x1 = Val() 39。*************X正向 i = 0 j = 0 i1 = 0 j1 = 0 For a = 1 To n i1 = i + L (i + x0, j + y0)(i1 + x0, j1 + y0), RGB(255, 0, 0) i = i1 Next a ElseIf xe 0 Then 39。************逐點(diǎn)法單步插補(bǔ) Static count As Integer Dim x0, y0, x1, y1, L, xe, ye As Single Dim n As Integer If SHURUchang = 1 Then count = 0 SHURUchang = 0 End If count = count + 1 x0 = Val() y0 = Val() x1 = Val() y1 = Val() L = Val() If L = 0 Then L = 1 = L End If If L 0 Then L = Abs(L) = L End If xe = x1 x0 ye = y1 y0 n = CInt(Abs(xe) / L) + CInt(Abs(ye) / L) flag1 = 0 If xe = 0 Then 39。******************第１象限插補(bǔ) i = 0 j = 0 i1 = 0 j1 = 0 f = 0 If count = n Then For m = 1 To count Step 1 If f = 0 Then i1 = i + L (i + x0, j + y0)(i1 + x0, j1 + y0), RGB(255, 0, 0) i = i1 j = j1 f = f Abs(ye) ElseIf f 0 Then j1 = j + L (i + x0, j + y0)(i1 + x0, j1 + y0), RGB(255, 0, 0) i = i1 j = j1 f = f +
畢業(yè)設(shè)計(jì)相關(guān)推薦
鄂ICP備17016276號(hào)-1