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一個簡單的火車票售票管理系統(tǒng)大全五篇-wenkub

2024-10-14 03 本頁面
 

【正文】 息管理系統(tǒng)”)。CNODE *c。//輸出售票紀(jì)錄(單張)void print_c_all(CNODE *)。//按購票人證件號搜索(限定某車次)void search_c_id_all(TNODE *,int)。//插入新的售票信息(單張)CNODE *insert_c_more(CNODE *)。//中序遍歷車次二叉排序樹(僅顯示車次信息)void inorder_all(TNODE *)。void create()。typedef struct tnode//車次信息類型 {char data。//票號int id。第一篇:一個簡單的火車票售票管理系統(tǒng)一個簡單的火車票售票管理系統(tǒng)(原創(chuàng))include include define MAX 100 define N 50typedef struct time//時間類型 {int x,y,z。//購票人證件號TIME date。//車次編號struct tnode *lchild,*rchild。//按車次建立二叉排序樹void insert(int)。//中序遍歷車次二叉排序樹(顯示車次及售票信息)void preorder(TNODE *)。//插入新的售票信息(批量)CNODE *del_c(CNODE *,CNODE *)。//按購票人證件號搜索(所有車次)void search_date(CNODE *,TIME)。//輸出售票紀(jì)錄(批量)TNODE *root=NULL。TIME d。for(i=0。printf(“”)。iprintf(“n請選擇您所需要的功能:”)。switch(func){case 1:printf(“nn車次信息管理n”)。printf(“”)。scanf(“%d”,amp。break。break。for(i=0。for(i=0。func)。case 2:t=search()。thead=del_c(thead,search_c(thead,no))。default:printf(“n[錯誤]功能號輸入有誤!請重新輸入!”)。iprintf(“”)。for(i=0。func)。no)。case 2:printf(“n請輸入您所要查詢的購票者證件號:”)。printf(“搜索完畢!自動返回上級菜單n...”)。,amp。else if(==2)if()ok=1。}while(!ok)。if(ok)search_date(search()head,d)。break。for(i=0。printf(“:先序遍歷車次”)。fflush(stdin)。if(root==NULL)printf(“[錯誤]無車次紀(jì)錄!”)。case 2:printf(“n+++指定車次已售票記錄n”)。}break。printf(“n”)。else{preorder(root)。break。default:printf(“n[錯誤]功能號輸入有誤!請重新輸入!”)。print_c_all(ptrhead)。printf(“%dt”,ptrdata)。preorder(ptrrchild)。return。ifor(j=0。head=headnext。for(i=0。printf(“n您所希望增加車次的數(shù)量:”)。iprintf(“新增第%d列車次:”,i+1)。iinsert(k[i])。rootlchild=rootrchild=NULL。amp。(p1rchild!=NULL))p1=p1rchild。p2data=m。return。p2data=m。return。p=root。while(p!=NULLamp。}}if(p==NULL)printf(“n該車次不存在!”)。p1=p2=root。key)。p2=p2lchild。return。if(p1rchild==p2)p1rchild=NULL。}}else{if(p2rchild==NULL){temp=p2lchild。}else if(p2lchild==NULL){temp=p2rchild。}else{p3=p2。}p2data=tempdata。printf(“車次 %d 已取消!nn”,key)。scanf(“%d”,amp。}while(p!=NULL)。printf(“購票日期(格式:yymmdd):”)。k)。}CNODE *insert_c_more(CNODE *head){int n,i。n)。}CNODE *search_c(CNODE *head,int id){CNODE *temp,*s。tempid!=id){s=temp。else return NULL。while(head!=NULL){if(headid==id){s=(CNODE *)malloc(sizeof(CNODE))。snext=head_s。printf(“n”)。search_c_id_all(ptrrchild,id)。sno=headno。head_s=s。}void search_date_all(TNODE *ptr,TIME t){if(ptr!=NULL){search_date_all(ptrlchild,t)。} }CNODE *del_c(CNODE *head,CNODE *p){CNODE *temp。}else{temp=pnext。}第二篇:火車票售票系統(tǒng) 需求分析報告三、需求規(guī)格說明書三、需求規(guī)格說明書1.引言...........................................................................................................................1 .............................................................................................................1 .............................................................................................................2 ....................................................................................................................2 .............................................................................................................2 2.任務(wù)概述....................................................................................................................2 ....................................................................................................................2 .............................................................................................................3 ..........................................................................................................3 3.?dāng)?shù)據(jù)描述....................................................................................................................3 .............................................................................................................3 .............................................................................................................3 ..........................................................................................................4 .............................................................................................................4 .............................................................................................................8 4.功能需求....................................................................................................................8 .............................................................................................................8 .............................................................................................................9 5.性能需求....................................................................................................................9 ..........................................................................................................9 .............................................................................................................9 .................................................................................................................9 6.運行需求....................................................................................................................9 .............................................................................................................9 ...........................................................................................................10 ...........................................................................................................10 ...........................................................................................................10 7.其它需求..................................................................................................................101.引言本需求分析報告的目的是規(guī)范化本軟件的編寫,旨在于提高軟件開發(fā)過程中的能見度,便于對軟件開發(fā)過程中的控制與管理,同時提出了本火車售票系統(tǒng)的軟件開發(fā)過程,便于程三、需求規(guī)格說明書序員與客戶之間的交流、協(xié)作,并作為工作成果的原始依據(jù),同時也表明了本軟件的共性,以期能夠獲得更大范圍的應(yīng)用。:包括提煉,分析和仔細(xì)審查已收集到的需求,以確保所有的風(fēng)險承擔(dān)者都明其含義并找出其中的錯誤,遺憾或其它不足的地方。b.《JAVA網(wǎng)絡(luò)高級編程》金勇華,曲俊生。2.任務(wù)概述(1)完善目前火車
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