polarizationjonesvectormatrices-wenkub
2023-05-01 10:53:16 本頁面
【正文】 rized light ? The electric field oscillations are only along the yaxis ? The Jones vector is then written, ? Where we have set the phase ?y = 0, for convenience ??????????????????????????????1000~~~AAeEEEE yioyoyoxo ?The normalized form is ??????107 Jones vector: Linearly polarized light at an arbitrary angle ? If the phases are such that ? = m? for m = 0, ?1, ?2, ?3, … ? Then we must have, and the Jones vector is simply a line inclined at an angle ? = tan1(Eoy/Eox) since we can write ? ?oyoxmyxEEEE 1??? ? ???????????????????s inc o s1~~~moyoxo AEEEx y ? The normalized form is 8 Circular polarization ? Suppose Eox = Eoy = A and Ex leads Ey by 90o=?/2 ? At the instant Ex reaches its maximum displacement (+A), Ey is zero ? A fourth of a period later, Ex is zero and Ey=+A x y t=0, Ey = 0, Ex = +A t=T/4, Ey = +A, Ex = 0 t=T/8, Ey = +Asin 45o, Ex = Acos45o 9 Circular polarization ? For these cases it is necessary to make ?y ?x . Why? ? This is because we have chosen our phase such that the time dependent term (?t) is negative ? ?? ?yxtkzioyytkzioxxeEEeEE??????????10 Circular polarization ? In order to clarify this, consider the wave at z=0 ? Choose ?x=0 and ?y=?, so that ?x ?y ? Then
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