流水生產(chǎn)組織ppt課件-wenkub
2023-05-16 06:49:53 本頁面
【正文】 工序所需設(shè)備數(shù)：? 2）混合流水線組織設(shè)計 ? (1) 混合流水線平均節(jié)拍 ： 產(chǎn)品品種數(shù)；??? ?nQFRni ie1? (2) 計算流水線最小可能工作地數(shù) ： ? 流水線計劃期的總勞動量： ? ?? pi ii tQL 1? 可能的最小工作地數(shù)： ????????????????????pi iipi ie QRtQFLS11m i n? (3) 繪制綜合工藝路線圖 ? 產(chǎn)品綜合工藝路線。 手工操作為主的工序同期化措施 1）分解和組合工序； 2）合理調(diào)配工人； 3）采用高效工具； Example of Line Balancing ? You’ve just been assigned the job a setting up an electric fan assembly line with the following tasks: T a s k T i m e ( M i ns ) De s c r i pti o n P r e de c e s s o r sA 2 As s e m b l e f r a m e No n eB 1 Mo u n t s w i t c h AC 3 . 2 5 As s e m b l e m o t o r h o u s i n g No n eD 1 . 2 Mo u n t m o t o r h o u s i n g i n f r a m e A, CE 0 . 5 At t a c h b l a d e DF 1 As s e m b l e a n d a t t a c h s a f e t y g r i l l EG 1 At t a c h c o r d BH 1 . 4 T e s t F, GExample of Line Balancing: Structuring the Precedence Diagram Task Predecessors A None A B A B C None C D A, C D Task Predecessors E D E F E F G B G H E, G H Example of Line Balancing: Precedence Diagram A C B D E F G H 2 1 .5 1 1 Question: Which process step defines the maximum rate of production? Answer: Task C is the cycle time of the line and therefore, the maximum rate of production. Example of Line Balancing: Determine Cycle Time R e q u i r e d C y c l e T i m e , C = P r o d u c t i o n t i m e p e r p e r i o dR e q u i r e d o u t p u t p e r p e r i o dC = 4 2 0 m i n s / d a y1 0 0 u n i t s / d a y = 4 . 2 m i n s / u n i tQuestion: Suppose we want to assemble 100 fans per day. What would our cycle time have to be? Answer: Example of Line Balancing: Determine Theoretical Minimum Number of Workstations Question: What is the theoretical minimum number of workstations for this problem? Answer: T h e o r e t i c a l M i n . N u m b e r o f Wo r k s t a t i o n s , NN = S u m o f t a s k t i m e s ( T )C y c l e t i m e ( C )ttN = 1 1 . 3 5 m i n s / u n i t4 . 2 m i n s / u n i t = 2 . 7 0 2 , o r 3tExample of Line Balancing: Rules To Follow for Loading Workstations ? Primary: Assign tasks in order of the largest number of following tasks. ? Secondary (tiebreaking): Assign tasks in order of the longest operating time A C B D E F G H 2 1 .5 1 1 Station 1 Station 2 Station 3 Task Followers Time (Mins) A 6 2 C 4 D 3 B 2 1 E 2 F 1 1 G 1 1 H 0 A C B D E F G H 2 1 .5 1 1 Station 1 Station 2 Station 3 A (=) Task Followers Time (Mins) A 6 2 C 4 D 3 B 2 1 E 2 F 1 1 G 1 1 H 0 A C B D E F G H 2 1 .5 1 1 A (=) B (=) Task Followers Time (Mins) A 6 2 C 4 D 3 B 2 1 E 2 F 1 1 G 1 1 H 0 Station 1 Station 2 Station 3 A C B D E F G H 2 1 .5 1 1 A (=) B (=) G (= .2) Idle= .2 Task Followers Time (Mins) A 6 2 C 4 D 3 B 2 1 E 2 F 1 1 G 1 1 H 0 Station 1 Station 2 Station 3 A C B D E F G H 2 1 .5 1 1 C ()=.95 Task Followers Time (Mins) A 6 2 C 4 D 3 B 2 1 E
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