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dcac直流交流逆變換器-wenkub

2023-05-21 12:39:17 本頁面
 

【正文】 113c o s13111c o s111{ c o s34??tttttttNNVpsd????????????????1cVAVBVCV?2cV2aV????2cV2bV??1aV?2aV?1bV2bV?( c) 矢量圖?302bV??( d ) 電壓波形合成2bv?1av2avpsdNNV ?psdNNV ?31psdNNV ?31)321( ?psdNNV ?)311( ?psdNNV ?31psdNNV ?Av?? ? 3030 a12ba12a vvvv 超前,滯后b2a2a1A vvvv ??? 24階梯波逆變器 o151aV1aV?2aV2aV?3aV4aV4bV3bV2bV1bV1cV2cV3cV4cV( b ) 繞組電壓矢量逆變器Ⅰ+dVAEI1AV1BV1CV逆變器Ⅱ+dVBFJ2BV2CV逆變器Ⅲ+dVCGK3AV3BV3CV逆變器Ⅳ+dVDHL4AV4BV4CVⅠⅡⅢⅣi aieea1aV1cV1bVj bjffb2aV2cV2bVk ckggc3aV3cV3bVl dlhhd4aV4cV4bV2AVABC2,CfjVe1,CeiVe4,aldVe3,akcVe3CgkgkVee?4ChlVe2,bbfVe1,baeVe3,bcgVe4,bdhVe1,aiaVe2,ajbVe( c ) 輸出電壓合成432211 bbababABVVVVVVV ??????四個(gè)逆變器依序相差1 5 度各繞組電壓均為1 2 0 度方波 24階梯波 逆變器 (續(xù) 1) mmmmm2mm2 mmmm2mnn2m2 m + n2 m + 2 n3 m + 2 n4 m + 2 n01Vb1Va-11VbaV?-2Vb2Va-22VbaV?-2m3bVn4bVnABV432211bbababABVVVVVVV??????輸出電壓波形合成 2c o s2c o s2111112221??VVVVVV????合成的基波電壓:階梯波的兩個(gè)相差 241?。任何時(shí)候有三個(gè)開關(guān)同,每個(gè)開關(guān)導(dǎo)電441 電壓型三相逆變器工作原理(續(xù) 3) 2dV2dV1T1D 3D3T 5T 5D4D4T 6T6D2D2Tai bi cia b cPQ0電路aibiciabibcicaiabccaaibiciabibcicai三角形負(fù)載abcaVaincibiccaV.abV.bcV.anV.abbnV.V. n1 . 51 . 531caV.?星形負(fù)載 )(31)(31)(31)(2....................bccaabbcbncaabancaabbnancaanabbnanVVVVVVVVVVVVVVVVVVVV????????????????441 電壓型三相逆變器工作原理(續(xù) 4) )(31)(31)(31.........bccaabbcbncaabanVVVVVVVVV??????負(fù)載星形連接時(shí):t?0abv?2?t?0bcv?2???2t?cav0t?anv0t?0t?bnv0vdVMdV32dV313?32 ?34 ?35 ?o1 80 導(dǎo)電波形負(fù)載相電壓階梯波方波線電壓三開關(guān)同時(shí)導(dǎo)電導(dǎo)電??1 2 0)(1 8 0441 電壓型三相逆變器工作原理(續(xù) 5) t?0abv?2?t?anv0dVMdV32dV31?????? ?????? ??tttttVtvdan ?????? 13s i n13111s i n1117s i n715s i n51s i n2)(ddm VVV 6 3 ?? ??????? ?????? ??tttttVtvdan ?????? 13c os13111c os1117c os715c os51c os2)(?????? ?????? ??tttttVtvdab ?????? 13s i n13111s i n1117s i n715s i n51s i n32)(ddm VVV ?? ??????? ?????? ??tttttVtvdab ?????? 13c os13111c os1117c os715c os51c os32)(442 電流型三相逆變器工作原理 ( a ) 電路: 星型負(fù)載RU dLdiT 1 T 3 T 5T 2T 6T 4a b cRRnai bici? ?2? ?2??2??2??2??2??2??2??2??2T 1t?t?t?t?t?t?t?t?t?t?V g1T 2T 3T 4T 5T 6 T 6V g2V g3V g4V g5V g6000000aibici0000abidIT 1T 2T 3T 4T 50120( b ) 波形( 導(dǎo)電類型)L大, iD恒定 120度導(dǎo)電模式,僅兩個(gè)開關(guān)同時(shí)導(dǎo)電 12, 23, 34, 45, 56, 61, 12 442 電流型三相逆變器工作原理(續(xù) 1) ( a ) 電路: 星型負(fù)載RU dLdiT 1 T 3 T 5T 2T 6T 4a b cRRnai bici??2??2
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