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【正文】 1 1 0 1 1 1 1 0 1 1 1 1 0 1 1 1 1 0 1 11 1 0 1 0 0 0 1 0 1[x*y]原 = 1， 11 0100 0101直接補(bǔ)碼陣列[x]補(bǔ) = (0)11011, [y]補(bǔ) = (1)00001(0) 1 1 0 1 1(1) 0 0 0 0 1(0) 1 1 0 1 1 (0) 0 0 0 0 0 (0) 0 0 0 0 0 (0) 0 0 0 0 0 (0) 0 0 0 0 00 (1) (1) (0) (1) (1)0 (1) (1) (0) (1) (1) 1 1 0 1 11, 0 0 1 0 1, 1 1 0 1 1 [x*y]補(bǔ) = 1,00101,11011（直接補(bǔ)碼陣列不要求） 帶求補(bǔ)器的補(bǔ)碼陣列[x]補(bǔ) = 0 11011, [y]補(bǔ) = 1 00001乘積符號(hào)位單獨(dú)運(yùn)算0⊕1＝1尾數(shù)部分算前求補(bǔ)輸出│X│＝11011，│y│＝111111 1 0 1 1* 1 1 1 1 1 1 1 0 1 1 1 1 0 1 1 1 1 0 1 1 1 1 0 1 1 1 1 0 1 11 1 0 1 0 0 0 1 0 1XY＝(2) 原碼陣列x = , y = 符號(hào)位: x0⊕y0 = 1⊕1 = 0[x]補(bǔ) = 11111, [y]補(bǔ) = 110111 1 1 1 11 1 0 1 11 1 1 1 11 1 1 1 1 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 0 1 0 0 0 1 0 1 [x*y]補(bǔ) = 0,11010,00101直接補(bǔ)碼陣列[x]補(bǔ) = (1)00001, [y]補(bǔ) = (1)00101(1) 0 0 0 0 1(1) 0 0 1 0 1(1) 0 0 0 0 1(0) 0 0 0 0 0 (1) 0 0 0 0 1 (0)0 0 0 0 0 (0) 0 0 0 0 01 (0) (0) (0) (0) (1)1 0 0 (1) (1) 0 0 0 1 0 10 1 1 0 1 0 0 0 1 0 1 [x*y]補(bǔ) = 0,11010,00101（直接補(bǔ)碼陣列不要求）帶求補(bǔ)器的補(bǔ)碼陣列[x]補(bǔ) = 1 00001, [y]補(bǔ) = 1 00101乘積符號(hào)位單獨(dú)運(yùn)算1⊕1＝0尾數(shù)部分算前求補(bǔ)輸出│X│＝11111，│y│＝110111 1 1 1 11 1 0 1 11 1 1 1 11 1 1 1 1 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 0 1 0 0 0 1 0 1XY＝ 8．(1) 符號(hào)位 Sf = 0⊕1 = 1 去掉符號(hào)位后：[y’]補(bǔ) = [y’]補(bǔ) = [x’]補(bǔ) = 0 0 1 1 0 0 0+[y’]補(bǔ) 1 1 0 0 0 0 1 1 1 1 1 0 0 1 0 ← 1 1 1 0 0 1 0+[y’]補(bǔ) 0 0 1 1 1 1 1 0 0 1 0 0 0 1 ← 0 1 0 0 0 1 0 +[y’]補(bǔ) 1 1 0 0 0 0 1 0 0 0 0 0 1 1 ← 0 0 0 0 1 1 0+[y’]補(bǔ) 1 1 0 0 0 0 1 1 1 0 0 1 1 1 ← 1 0 0 1 1 1 0+[y’]補(bǔ) 0 0 1 1 1 1 1 1 1 0 1 1 0 1 ← 1 0 1 1 0 1 0+[y’]補(bǔ) 0 0 1 1 1 1 1 1 1 1 1 0 0 1 (2) 符號(hào)位 Sf = 1⊕0 = 1 去掉符號(hào)位后：[y’]補(bǔ) = [y’]補(bǔ) = [x’]補(bǔ) = 0 0 0 1 0 1 1+[y’]補(bǔ) 1 1 0 0 1 1 1 1 1 1 0 0 1 0 0 ← 1 1 0 0 1 0 0+[y’]補(bǔ) 0 0 1 1 0 0 1 1 1 1 1 1 0 1 ← 1 1 1 1 0 1 0+[y’]補(bǔ) 0 0 1 1 0 0 1 0 0 1 0 0 1 1 ← 0 1 0 0 1 1 0+[y’]補(bǔ) 1 1 0 0 1 1 1 0 0 0 1 1 0 1 ← 0 0 1 1 0 1 0+[y’]補(bǔ) 1 1 0 0 1 1 1 0 0 0 0 0 0 1 ← 0 0 0 0 0 1 0+[y’]補(bǔ) 1 1 0 0 1 1 1 1 1 0 1 0 0 1 9．(1) x = 2011*, y = 2010*() [x]浮 = 11101, [y]浮 = 11110, ExEy = 11101+00010=11111[x]浮 = 11110,(1)x+y 0 0. 0 1 0 0 1 0 (1) + 1 1. 1 0 0 0 1 01 1. 1 1 0 1 0 0 (1) 規(guī)格化處理: 階碼 11100 x+y= *24 = 24*xy 0 0. 0 1 0 0 1 0 (1)+ 0 0. 0 1 1 1 1 0 0 0 1 1 0 0 0 0 (1) 規(guī)格化處理: 階碼 11110xy=22*(2) x = 2101*(), y = 2100* [x]浮= 11011, [y]浮= 11100, ExEy = 11011+00100 = 11111[x]浮= 11100,(0)x+y 1 1. 1 1 0 1 0 1 + 0 0. 0 1 0 1 1 00 0. 0 0 1
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