混凝土設計基本原理-第7章受扭構(gòu)件的扭曲截面承載力-文庫吧
2025-01-04 03:59 本頁面
【正文】 Failure（全部超筋 ） Compression failure When two types of torsional reinforcements are excessive , the reinforcements do not yield before concrete crushes. When one type of torsional reinforcements is excessive , the excessive reinforcements do not yield before concrete crushes. Check the minimum dimension of section（最小截面尺寸驗算） Control the ratio of longitudinal bars to stirrups （ ?） Torsional capacity of member under pure torsion （純扭構(gòu)件抗扭承載力） 開裂扭矩（ Cracking torque) Tcr 45 176。 F1 F2 F3 F4 tttcr WfbhbfT ??? )3(6.2ttcr WfT ??? ?tPrinciple stress If concrete is ideal plastic material, member cracks when principle stresses at all points of section exceed tensile strength (若混凝土時理想塑性，則截面上所有點的主拉應力達到抗拉強度構(gòu)件才開裂） Torsional capacity of member with torsional reinforcements（配筋受扭構(gòu)件承載力） (1) 力學模型 空間桁架（ space truss analogy） Longitudinal bars tension chords（受拉弦桿） Stirrupstension web members（受拉腹桿） concretepression diagonals （受壓斜桿） cosD ?DsinD ?2d c o rTqtA???c o sF F D ???13sin c o rD q b? ?c o s c o s c o tsi n13 c o r c o rqbF F D q b? ? ? ?? ? ??39。39。 c otc orF F qh ???12c o t c o t2 c o rc o rc o rTuF q uA?????13片 水平力和豎向力平衡 3F1F箍筋 corN qb??假設鋼筋均屈服 ta n1 2s t y vc o rTN A f sA?? ?c o t2 c o rs tl yc o rTuF A fA??? ?ta n 1 1y v s t c o ry s tlf A uf A s? ???T 12 y v s t c o ru f A As??1y stlyv st corf A sf A u? ?1Ncorbcotcorb ?3F1F箍筋 / / ( c o t / ) ta n ta n1 2c o r c o rc o rTN N n q b b s q s sA? ? ?? ? ? ??(2) Torsional capacity of rectangular member under pure torsion（矩形截面純扭構(gòu)件受扭承載力） c o rstyvttscu AsAfWfTTT ?????? ?yvyc o rsts tlffuAsA1??T member and Ⅰ shaped member under pure torsion（ T形和工形截面構(gòu)件純扭） ? The section is divided into several rectangular section.（截面分割成幾個矩形部分）
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