計(jì)算機(jī)網(wǎng)絡(luò)實(shí)驗(yàn)報(bào)告-實(shí)驗(yàn)五 探索tcp協(xié)議-文庫(kù)吧
2025-05-13 00:54 本頁(yè)面
【正文】 ply to the SYN? What is the value of the ACKnowledgement field in the SYNACK segment? How did determine that value? What is it in the segment that identifies the segment as a SYNACK segment? 答： The sequence number of the SYNACK segment sent by is:0； SYNACK segment 中 ACKnowledgement 的值為 1； ACKnowledgement number 的值為 SYN 消息中 sequence number 加上 1 所得； SYN 和 Acknowledgement f 都置為 1 說(shuō)明這是一個(gè) SYNACK segment. 6. What is the sequence number of the TCP segment containing the HTTP POST mand? Note that in order to find the POST mand, you’ll need to dig into the packet content field at the bottom of the Wireshark window, looking for a segment with a “POST” within its DATA field. Sequence number The value of the ACKnowledgement field － 8－ 答： 第四號(hào)報(bào)文段是包含 HTTP POST 命令的 TCP 1. Sequence number Post mand segment － 9－ 7. Consider the TCP segment containing the HTTP POST as the first segment in the TCP connection. What are the sequence numbers of the first six segments in theTCP connection (including the segment containing the HTTP POST)?At what time was each segment sent? When was the ACK for each segment received?Given the difference between when each TCP segment was sent, and when itsacknowledgement was received, what is the RTT value for each of the sixsegments? What is the EstimatedRTT value (see page 249 in text) after thereceipt of each ACK? Assume that the value of the EstimatedRTT is equal tothe measured RTT for the first segment, and then is puted using theEstimatedRTT equation on page 249 for all subsequent : Wireshark has a nice feature that allows you to plot the RTT foreach of the TCP segments sent. Select a TCP segment in the “l(fā)isting ofcaptured packets” window that is being sent from the client to server. Then select: StatisticsTCP Stream GraphRound Trip Time Graph. Segment 16 are ,5,7,8,10 － 10－ Segment 1 Segment 2 Segment 3 Segment 4 Sequence number=1 Sequence number=566 Sequence number=2026 － 11－ Segment 5 Segment 6 答： 前 6 個(gè)報(bào)文段為 ,5,7,8,10,11. 對(duì)應(yīng)的 ACK 分別為 ,9,12,14,15,16. 前 6 個(gè)報(bào)文段截圖如下： Sequence number=3486 Sequence number=4946 Sequence number=6406 － 12－ 報(bào)文段的序列號(hào)為每個(gè)報(bào)文段的首字節(jié)加 1，所以序列號(hào)為： Segment 1 sequence number:1 Segment 2 sequence number:566 Segment 3 sequence number:2026 Segment 4 sequence number:3486 Segment 5 sequence number:4946 Segment 6 sequenc
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