【正文】 if(a[i]%3==0amp。printf(“n3,5,7:n”)。printf(“%4d”,a[i])。for(i=0。printf(“Please input numbers:n”)。} ，然后再輸出其中同時(shí)是7倍數(shù)的數(shù)。if(a[i]if(a[i]==0)count3++。a[i])。for(i=0。int i,count1=0,count2=0,count3=0。} ，分別統(tǒng)計(jì)其中正數(shù)、負(fù)數(shù)、零的個(gè)數(shù)。if(flag==2)printf(“nDeng ”)。if(flag==0)printf(“nCan not!n”)。if(a+bflag=2。b,amp。scanf(“%f,%f,%f”,amp。/* Note:Your choice is C IDE */ include “” main(){float a,b,c,flag。}printf(“x=%ld,y=%ld”,x,y/10)。digit=x%10。y=digit。x)。/*個(gè)位數(shù)、原始數(shù)、逆數(shù)*/printf(“Please input the old number:n”)。else printf(“Wrong password!n”)。i++。break。continue。while(iif(strlen(password)!=6){ printf(“The string length is wrong!Retry please!n”)。char password[N]。否則轉(zhuǎn)⑤；⑤ 回答三次口令了嗎？如果沒有，計(jì)數(shù)器加1后（i++），轉(zhuǎn)③，否則轉(zhuǎn)⑥；⑥ 根據(jù)flag之值輸出相應(yīng)信息。}printf(“sum=%ld”,sum)。sum+=s。i=1。long s=0,sum=0。① 設(shè)置環(huán)境；② 定義變量i、j、s，以及用于放置結(jié)果的變量sum，并令sum初值為0；③ i=1；④ 如果i≤100，則轉(zhuǎn)⑤，否則轉(zhuǎn)⑧；⑤ 令s=0，求前i個(gè)自然數(shù)之和，并放于變量s之中；⑥ sum=sum+s； ⑦ i增加1，轉(zhuǎn)④； ⑧ 輸出和sum，結(jié)束。} }printf(“count=%4d”,count)。i%5!=0){printf(“%4d”,i)。iif(i%3==0amp。} } ，分別是哪些？/* Note:Your choice is C IDE */ include “” main(){int i,count=0。case 10:printf(“Ten!”)。case 9:printf(“Nine!”)。case 8:printf(“Eight!”)。case 7:printf(“Seven!”)。case 6:printf(“Six!”)。case 5:printf(“Five!”)。case 4:printf(“Four!”)。case 3:printf(“Three!”)。case 2:printf(“Two!”)。} switch(n){case 1:printf(“One!”)。scanf(“%d”,amp。n)。printf(“Please input n:n”)。}} ~10之間的一個(gè)數(shù)字，輸出它對應(yīng)的英文單詞。sw==gw){printf(“nThe number is:%dn”,i)。if(qw==bwamp。sw=i/10%10。qw=i/1000。for(i=1122。請根據(jù)以上線索找出車號?，F(xiàn)場有三人目擊事件，但都沒有記住車號，只記下車號的一些特征。printf(“The number is:%”,sqrt(sum))。amp。}for(i=1。scanf(“%d”,amp。n)。printf(“Please input n:n”)。/* Note:Your choice is C IDE */ include “” include “” main(){ int n,s,i。}（不包括n）同時(shí)能被3和7整除的所有自然數(shù)之和的平方根s，n從鍵盤輸入。kfor(n=1。ifor(j=1。/* Note:Your choice is C IDE */ include “” main(){ int i,j,k,n。iprintf(“%4d”,b[i])。printf(“nThe new numbers are:n”)。for(i=0。ib[Ni1]=a[i]。printf(“Please input numbers:n”)。} （鍵盤）將5個(gè)整數(shù)輸入到數(shù)組a中，然后將a逆序復(fù)制到數(shù)組b中，并輸出b中各元素的值。count++。a[i])。for(i=0。、/* Note:Your choice is C IDE */ include “” define N 20 main(){int a[N],i,sum=0,count=0。}printf(“sum=%ld”,sum)。for(i=1。scanf(“%d”,amp。printf(“1+2+3+....+nn”)。/* Note:Your choice is C IDE */ include “” main(){int n,i。}else printf(“The old number equals the new number:%ld”,n)。printf(“The old number is:%ldn”,n)。n{sw=n/10。}else if(n=10amp。printf(“The old number is:%ldn”,n)。sw=n/10%10。amp。printf(“The new number is:%d%d%d%dn”,gw,sw,bw,qw)。gw=n%10。bw=n/100%10。amp。printf(“The new number is:%d%d%d%d%dn”,gw,sw,bw,qw,ww)。gw=n%10。bw=n/100%10。nww=n/10000。} if(n=10000amp。scanf(“%ld”,amp。n)。printf(“Please input:n”)。/* Note:Your choice is C IDE */ include “” main(){ long n。第一篇：C語言上機(jī)練習(xí)題上機(jī)練習(xí)題，輸出其逆數(shù)。例如輸入12345，輸出應(yīng)為54321。int ww,qw,bw,sw,gw。scanf(“%ld”,amp。while(n99999){printf(“nThe number is 2 little or too please!n”)。n)。amp。qw=n/1000%10。sw=n/10%10。printf(“The old number is:%ldn”,n)。} else if(n=1000amp。nqw=n/1000。sw=n/10%10。printf(“The old number is:%ldn”,n)。} else if(n=100amp。nbw=n/100。gw=n%10。printf(“The new number is:%d%d%dn”,gw,sw,bw)。amp。gw=n%10。printf(“The new number is:%d%dn”,gw,sw)。}+2+3?+n的值，n是從鍵盤輸入的自然數(shù)。long sum=0。printf(“Please input n:n”)。n)。isum+=i。}（鍵盤）讀入20個(gè)數(shù)據(jù)到數(shù)組中，統(tǒng)計(jì)其中正數(shù)的個(gè)數(shù)，并計(jì)算這些正數(shù)之和。printf(“Please input numbers :n”)。i{ scanf(“%d”,amp。if(a[i]0){ sum+=a[i]。}} printf(“count=%d,sum=%d”,count,sum)。/* Note:Your choice is C IDE */ include “” define N 5 main(){ int a[N],b[N],i。for(i=0。} printf(“nThe old numbers are:n”)。iprintf(“%4d”,a[i])。for(i=0。} ，換成等值的50元，20元，10元，5元一張的小鈔票，每種面值至少1張，編程輸出所有可能的換法，程序應(yīng)適當(dāng)考慮減少重復(fù)次數(shù)。for(i=1。jfor(k=1。nif(i*50+j*20+k*10+n*5==500)printf(“num50=%d,num20=%d,num10=%d,num5=%dn”,i,j,k,n)。例如若n為1000時(shí)，函數(shù)值應(yīng)為：s=。float sum=0。scanf(“%d”,amp。while(nprintf(“nError please:n”)。n)。iif(i%3==0amp。i%7==0)sum+=i。}，撞人后逃跑。甲說：牌照的前兩位數(shù)字是相同的；乙說：牌照的后兩位數(shù)字是相同的，但與前兩位不同；丙是數(shù)學(xué)家，他說：四位的車號剛好是一個(gè)整數(shù)的平方。/* Note:Your choice is C IDE */ include “” include “” main(){int i,qw,bw,sw,gw。iif(sqrt(i)!=(int)sqrt(i))continue。bw=i/100%10。gw=i%10。amp。break。/* Note:Your choice is C IDE */ include “” main(){ int n。scanf(“%d”,amp。while(n10){printf(“Error input!Retry please:n”)。n)。break。break。break。break。break。break。break。break。break。break。for(i=106。amp。count++。}，試寫程序。/* Note:Your choice is C IDE */include “” main(){int i,j。printf(“1+1+2+1+2+3+1+2+3+4+....1+2+3+..+nn”)。while(is+=i。i++。} ：① 設(shè)置環(huán)境；② 定義變量i、flag和password，并令flag=0，i=0；③ 用戶回答口令，將其賦于password變量；④ 口令正確？如果是，則flag=1，轉(zhuǎn)⑥。/* Note:Your choice is C IDE */ include “” include “”define N 6 main(){ int i=0,flag=0。printf(“The password is:123456n”)。i++。}if(strcmp(“123456”,password)==0){flag=1。}else { printf(“Wrong input!Retry please!n”)。} } if(flag==1)printf(“Right password!n”)。}下：① 設(shè)置環(huán)境；② 定義變量digit、x、y分別表示原始數(shù)、原始數(shù)的個(gè)位數(shù)和逆數(shù)；③ 輸入原始正整數(shù)x；④ 從x中分解出個(gè)位數(shù)字digit；⑤ 合并個(gè)位digit至逆數(shù)y中；⑥ 原始數(shù)x縮小10倍：x=x/10；⑦ 如果x非零，則轉(zhuǎn)④； ⑦ 輸出逆數(shù)y，結(jié)束/* Note:Your choice is C IDE */include “” main(){long digit,x,y。scanf(“%ld”,amp。digit=x%10。while(x!=0){x=x/10。y=y*10+digit。}，判斷出這是個(gè)什么三角形（等腰、等邊、任意，或不能構(gòu)成）。/*flag=0不能，flag=1等邊,flag=2等腰，flag=3任意*/printf(“Please input angles:n”)。a,amp。c)。else flag=3。if(flag==1)printf(“nDeng ”)。if(flag==3)printf(“nPu ”)。include “” define N 10 main(){ int a[N]。/*count1記錄正數(shù)個(gè)數(shù)，count2記錄負(fù)數(shù)個(gè)數(shù)，count3記錄0的個(gè)數(shù)*/ printf(“Please input numbers:n”)。iscanf(“%d”,amp。if(a[i]0)count1++。} printf(“count1=%4d,count2=%4d,count3=%4d”,count1,count2,count3)。（設(shè)N為100）/* Note:Your choice is C IDE */ include “” define N 100include include main(){int a[N],i。randomize()。i{ a[i]=random(900)+100。}printf(“nn”)。for(i=0。amp。amp。}~200中的完全平方數(shù)。for(i=100。}，判斷這三個(gè)數(shù)能否構(gòu)成直角三角形。/*flag=0不能，flag=1能*/ printf(“Please input angles:n”)。a,amp。c)。a,amp。c)。else flag=0。else printf(“nCan not!”)。/* Note:Your choice is C IDE */ include “” define N 10 include “” include “” include “” main(){ char c[N]。gets(c)。while(i!=strlen(c)){if(isupper(c[