用ansys進(jìn)行滯回分析-文庫(kù)吧資料
2025-07-01 18:43本頁(yè)面
【正文】 outres,all,allnropt,full/solu*enddo*do,ii,1,15mat,1SECTYPE,1, BEAM, RECT, pier, 0SECOFFSET, CENTSECDATA,10,10,0,0,0,0,0,0!TBPT,DEFI,!TBPT,DEFI,TBPT,0!等向強(qiáng)化!隨動(dòng)強(qiáng)化mp,nuxy,1,et,1,beam188n,17,0,1000n,1,/clear命令流如下：分別采用了隨動(dòng)強(qiáng)化和等向強(qiáng)化兩種強(qiáng)化準(zhǔn)則。*ENDDOOUTRES,ALL,ALLACEL,AC(I),0,0BETAD,2*DAMPRATIO/(FREQ1*2*)TRNOPT,FULL/SOLU*GET,FREQ1,MODE,1,FREQFINIMXPAND,8, , ,1ANTYPE,2()*DIM,AC,NT*SET,NT,1001D,1,all,14,13,ESYS, 0MAT, 1/REPLOT/EFACET,1/SHRINK,0LESIZE,ALL,1, , , , , , ,1LATT,1,2,1, , , ,LATT,1,1,1, , , ,LSTR,2,4LSTR,1,3K,4,6,6,K,2,6,MPDATA,DENS,1,2500MPTEMP,MPDATA,EX,1,3e10R,3, ,5000000, , !阻尼器線性系數(shù)C1MPTEMP,R,1, , , ,KEYOPT,2,2,0ET,2,COMBIN14solve *enddo finish那么怎么提取滯回?cái)?shù)據(jù)呢/PREP7allsel,all nsubst,40,0,0 d,all,ux,disp(i) nsel,s,loc,z,200 time,i *do,i,2,6 solve ALLSEL,ALL d,all,ux,disp(1) nsubst,1,0,0 nsel,s,loc,z,200 time, !施加位移荷載 !進(jìn)入solution階段 /solu nlgeom,on sstif,off autots,on outres,all,all outpr,all,all disp(6)=wlw1 disp(5)=0 disp(4)=wlw1 dis
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