用ansys進行滯回分析(參考版)
2025-06-28 18:43本頁面
【正文】 save。SOLVE *ENDDODK,s_num+1, ,235*s_length*disp(i)/6/, ,0,UX, , , , , ,！位移加載 autots,on OUTRES,ALL,1 kbc,0！斜坡荷載 *dim,disp,number *VREAD,disp(1),disp2,txt,IJK,number ()！讀荷載數(shù)組 *DO,I,1,NUMBERvtol,u,0NSUBST,100,10000,10sstif,offnropt,full,onpred,offnlgeom,on施加的位移為： 0,5,0,5,0,10,0,10,0,15,0,15,0 提供一個本人做支撐位移控制低周往復荷載下命令流，希望能對你有幫助 /solu ！求解選項設(shè)置 ANTYPE,STATICMSHKEY,1 AMESH,1 NSEL,S,LOC,Y,200 CP,1,UX,ALL SAVE FINISH1 ESIZE,5,0, MSHAPE,0,2D1 REAL, MAT,1TBDATA,235,3000, k,1 k,2,50 k,3,50,200 k,4,0,200 a,1,2,3,4 TYPE,TB,BKIN,1,1,2,1MP,PRXY,1,ET,1,SHELL63 R,1,3, , , , , , MP,EX,1,+005 fini /clear /PREP7我在分析一懸臂板的滯回曲線時，底邊固定，頂部節(jié)點X方向的自由度耦合(編號為1)，頂部節(jié)點采用位移加載，命令流如下。NSOL,2,22,U,z,Uz/post26FINISHSOLVE/STATUS,SOLUTIME,9OUTRES,BASIC,40NSUBST,40,0,0D,22, , %DIS% , , , ,UZ, , , , ,DIS(1,1) = 0,3,0,3,0,4,0,4,0DIS(1,0) = 0,1,2,3,4,5,6,7,8*DIM,dis,TABLE,9,1,TIME, ,DA,3,ALL,采用隨動強化時的滯回曲線如下圖：save*enddo!lswrite,tt+1nsubst,10,solved,16,tt*,uytime,tt
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