催化工程第四章-1氣固多相催-資料下載頁
2024-12-31 13:29本頁面
【正文】 ? ???26464646464848484 )(HHCHCHCHCHCHCHCgHCk???????????? ???? ???? ???? ???26464646464848484 )(HHHCHCHCHCHCHCgHCk42 Ckr ?? 02 84? HCkr 084 ?? HCkr ????????????? ???? ???? ???? ???2264646464848484 )(HHHCHCHCHCHCHCgHCk? 根據(jù) langmuir混合氣體吸附等溫 式得到 ? 因為 C4H8 ,C4H6 H2的吸附都很弱，所以 ? ? 1 ? 對丁烯而言是一級反應 226464848422646484848484841 110 HHHCHCHCHCHHHCHCHCHCHCHCHCpppppp p??????? ??????????226464848422646484848484841110HHHCHCHCHCHHHCHCHCHCHCHCHCppppppp?????????????????226464848422646484848484841110HHHCHCHCHCHHHCHCHCHCHCHCHCppppppp?????????????????2264648484 HHHCHCCHC ppp ??? ??2264648484 HHHCHCHCHC ppp ??? ??848484 HCHCHC pkpkr ??? ? 848484HCHCHC pkpkr ??? ?? 根據(jù)流動體系的動力學方程式 ? 將 代入 ??AxAAArdxFV00?? AxAAA rdxFV0084HCA kpr ?84 HCA kpr ???0FV ??AxAAA kpdxV00? 設丁烯進入反應器的摩爾流量為 FA0,反應器某截面上的轉(zhuǎn)化率為 XA,則該截面上各物質(zhì)的摩爾流量為： ? 在時間為 t時體系的總摩爾為 400nC xFFn AAAA ??AAHAAHCAAAAxFnxFnxFFn0206400????)1(0 0000 AA AAAAAAA xF xFxFxFF ?? ??? )1(00000AAAAAAAAAxFxFxFxFF?????? 丁烯的分壓為 (p=1atm) ? 將此結果代入積分式得 )1()1()1()1(00AAAAAAAxxxFpxFp??????)1()1()1()1(00AAAAAAAxxxFpxFp??????? ?????????1())1()1()1()1(1(1000AAAAAAAAxxxFpxFpkFVkFVA 10 ? ? ??? AxAAA xxkFV0 )1()1(10dxxxkFVAxAAA? ???0 )1()1(10? 積分后得到 )1(0AAA xxVFk ???)1 (0 AAA xxVFk ???謝謝觀看 /歡迎下載 BY FAITH I MEAN A VISION OF GOOD ONE CHERISHES AND THE ENTHUSIASM THAT PUSHES ONE TO SEEK ITS FULFILLMENT REGARDLESS OF OBSTACLES. BY FAITH I BY FAITH
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