【正文】
111 ??? RUI A6A22102S1 ????? IIIa I R IS b I1 R1 (c) IR1 I R1 R IS R3 + _ IU1 +_ UIS U R2 +_ U1 a b (a) a I R1 R IS +_ U1 b (b) (2)由圖 (a)可得: A4A4A2S1R --- ??? IIIA2A51031R3 ??? RUI理想電壓源中的電流 A6A)4(A2R1R3U1 ??? --- III理想電流源兩端的電壓 V10V22V61S2S2IS ????????? IRRIIRUUa I R IS b I1 R1 (c) a I R1 R IS +_ U1 b (b) 各個電阻所消耗的功率分別是: W36=61== 22RIP RW16=41== 22 111 )(-RR IRPW8=22== 22S22 IRP RW20=25== 22333 RR IRP兩者平衡: (60+20)W=(36+16+8+20)W 80W=80W (3)由計算可知,本例中理想電壓源與理想電流源都是電源,發(fā)出的功率分別是: W60=610== 111 UU IUPW20=210== SSS IUP IIClass Over Restrooms Telephones Refreshments