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【正文】 of the WCDMA? ( A )A. Transfers。 B. PN code。 C. RAKE。 D. Power control.18. Which of the following is core technique of the TDSCDMA? ( B ) A. Transfers。 B. Smart antennas。 C. Encoding。 D. Error control.19.The GSM spectral allocation is 25MHz for base transmission (935—960MHz) and 25MHz for mobile transmission ( D ). A. 935—960MHz。 B. 1805—1880MHz。 C. 1710—1785MHz。 D. 890—915MHz.20.Third generation system mostly prise the ( A ). A. UTRAN, CN and UE。 B. MS, MSC and BS。 C. MS, RAN and CN。 D. RAN, CN and BS.21.A base station subsystem (BSS) consists of ( B ). A. a base station。 B. a base station controller and one or more base transceiver stations。 C. a base station controller and a radio antenna。 D. one or more base transceiver stations.22.Fading effects in a mobile environment can be classified as either ( D ). A. fast or slow。 B. fast and slow。 C. fast。 D. slow.23.( D ) is the procedure for changing the assignment of a mobile unit from one BS to another as the mobile unit moves from one cell to another. A. Transmission。 B. change。 C. divert。 D. Handoff.24.Fast fading is due to reflections of local objects and the ( D ) of the terminal relative to those objects. A. multipath。 B. environment。 C. large reflectors。 D. motion.25.Third generation system mostly prise the ( A ). A. RAN and CN。 B. MS and BS。 C. MS and CN。 D. RAN and BS.26. The cellular mobile munication system consist of three parts, they are ( B ).A. TDMA, FDMA and CDMA。 B. BS, NS and MS。 C. CDMA2000,WCDMA and CDMA。 D. FDD, TDD and FHSS.27.Second generation standards use digital modulation formats and ( A )and CDMA/FDD multiple access techniques. 注意:A和B答案相同 A. TDMA/FDD。 B. TDMA/FDD;;D. TDMA/TDD28.Two techniques for multiplexing in telemunications network are in mon use, they are ( D ).A. CDMA and TDMA。 B. FDMA and TDMA。 C. FDMA and CDMA。 D. TDM and FDM.29.A GSM cell can have a radius of between( B ), depending on the environment.A. 100 m and 5kmB. 100m and 35km。 C. 100m and 50km。 D. 100m and 100km.30.As a general rule of thumb, we must keep the “( A )Fresnel zone” free of obstructions in order to obtain transmission under freespace conditions.A. first。 B. secondly。 C. thirdly。 D. fourthly.31.Thermal noise is due to thermal agitation of ( B ).A. molecules。 B. electrons。 C. particles。 D. photon.32.Third generation system mostly prise the ( A ).A. RAN and CN。 B. MS and BS。 C. MS and CN。 D. RAN and BS.33. The same frequency assignments cannot be made in adjacent cell because of ( B ).A. multipleaccess interference。 B. interchannel interference。C. cochannel interference。 D. coantenna interference..計(jì)算題:1. Given a receiver with an effective noise temperature of 249K and a 10MHz bandwidth, the thermal noise level at the receiver’s output is Solution: 2. Given a receiver with an effective noise temperature of 300K and a 10MHz bandwidth, the thermal noise level at the receiver’s output is Solution: , hT =100m, hR =2m, and d=10km. estimate the path loss for a mediumsize city.Solution: , and . Estimate the path loss for a mediumsize city. Solution: 11 / 11
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