moa計(jì)算的實(shí)例ppt課件(編輯修改稿)
2025-02-10 04:30 本頁(yè)面
【文章內(nèi)容簡(jiǎn)介】 R O M A G N E T I C C A L C U L A T I O N O F P O W E R E Q U I P M E N T? ! This progam is designed to caculate the potential distribution on MOA ? ! with developed by Dr. Ji Shengchang, Xi39。an Jiaotong University ? ! for ZhengTai Ceramic Works,2022. ? /FILNAME,MOA !Jobname。 ? !Part 1: Initializing geometry data。 ? Rf=266E03 !Radius of flange and tower。 ? R_FED=10*Rf !Radius of finite element domain。 ? Roc=130E03 !Outer radius of ceramic column。 ? Ric=100E03 !Inner radius of ceramic column。 ? Ro_ZnO= !Radius of outer ZnO slice 。 ? Ri_ZnO= !Radius of inner Zno slice。 ? Rs=50E03 !Radius of bigger shield circle。 ? Rssmall=50E03 !Radius of smaller shield circle。 ? R3=(800E03)Rs !Outer Radius of bigger shield circle。 800E03 ? R3small=450E03 !outer Radius of smaller shield circle。450E03 ? R4= ? Tc=82E03 !Thickness of aluminum cashion。 ? Le= !Length of MOA element。~*54 ? Ht=422E03 !Height of tower。 ? Hf=102E03 !Height of flage。 ? H=+Ht !Total height。 ? H1=Ht+Hf+Tc+Le ? H2=Ht+3*(2*(Hf+Tc)+Le) ? H3=(900E03)Rs !the depth of shield circle_the primary value is 900E03 ? H3small=50E03 !the depth of small shield circle_the primary value is 50E03 ? H_FED=*H 參數(shù)化結(jié)構(gòu)尺寸 119 A P P L I C A T I O N o f A N S Y S O N E L E C T R O M A G N E T I C C A L C U L A T I O N O F P O W E R E Q U I P M E N T? /PREP7 ? K,R_FED,0 ? K,Rf,0 ? K,Rf,Ht ? K,Rf,Ht+Hf ? K,Roc,Ht+Hf ? K,Roc,Ht+Hf+Tc ? K,Ric,Ht+Hf+Tc ? K,Ro_ZnO,Ht+Hf+Tc ? K,Ri_ZnO,Ht+Hf+Tc K,0,Ht+Hf+Tc K,0,H1 L,1,2 *Repeat,10,1,1 LDrag,9,8,7,6,10 K,Roc,H1+Tc K,Rf,H1+Tc K,Rf,H1+Tc+Hf L,11,12 *Repeat,7,1,1 LGen,3,3,21,1,0,2*(Hf+Tc)+Le NumMrg,All !Four MOA elements have made. 建立有限元模型 （自下而上的建模方法） 120 A P P L I C A T I O N o f A N S Y S O N E L E C T R O M A G N E T I C C A L C U L A T I O N O F P O W E R E Q U I P M E N T? K,0,H2 ? L,19,50 ? Cyl4,R3,HH3,0,0,Rs,360 ? Cyl4,R3small,HH3small,0,0,Rssmall,360 ? K,0,H_FED ? K,R_FED,H_FED ? L,19,58 ? L,58,59 ? L,1,59 K,0,2*H_FED K,2*R_FED,2*H_FED K,2*R_FED,0 L,58,60 L,60,61 L,59,61 L,61,62 L,1,62 NumCmp,All 續(xù) 建立有限元模型 （自下而上的建模方法） 121 A P P L I C A T I O N o f A N S Y S O N E L E C T R O M A G N E T I C C A L C U L A T I O N O F P O W E R E Q U I P M E N T? !Part 2: Creating areas and operating some lines, areas。 ? *Do,I,0,2 AL,6+I*19,13+I*19,14+I*19,18+I*19 AL,7+I*19,
教學(xué)課件相關(guān)推薦
鄂ICP備17016276號(hào)-1